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New posts in roots
Why does the discriminant of a cubic polynomial being less than $0$ indicate complex roots?
algebra-precalculus
polynomials
roots
symmetric-polynomials
Must imaginary roots come in conjugate pairs?
polynomials
complex-numbers
roots
A positive polynomial is the sum of two squares in $\mathbb{R}[X]$ [duplicate]
polynomials
roots
Why not write the solutions of a cubic this way?
algebra-precalculus
polynomials
roots
Irrationality of $(a_1+\sqrt{b_1})(a_2+\sqrt{b_2})$
abstract-algebra
ring-theory
field-theory
roots
irrational-numbers
Solve for $x$: $\frac{x^2-10x+15}{x^2-6x+15}=\frac{3x}{x^2-8x+15}$
algebra-precalculus
roots
The trigonometric solution to the solvable DeMoivre quintic?
trigonometry
special-functions
roots
radicals
Solving a cubic polynomial equation.
polynomials
roots
transformation
cubics
Roots of minimal and characteristic polynomials
matrices
polynomials
roots
minimal-polynomials
characteristic-polynomial
Square root of $2$ is irrational
algebra-precalculus
elementary-number-theory
roots
integers
substitution
$\sqrt[31]{12} +\sqrt[12]{31}$ is irrational
abstract-algebra
algebra-precalculus
roots
extension-field
irrational-numbers
Does "eff" mean to describe in words?
meaning
etymology
roots
How to solve polynomial equations in a field and/or in a ring?
polynomials
ring-theory
field-theory
roots
Prove using Rolle's Theorem that an equation has exactly one real solution.
real-analysis
derivatives
roots
rolles-theorem
How to show that a root of the equation $x (x+1)(x+2) ....... (x+2009) = c $ can have multiplicity at most 2?
functions
polynomials
numerical-methods
roots
Why A is pronounced differently in "opacity" and "opaque"
pronunciation
latin
roots
What does this converge to and why?
algebra-precalculus
convergence-divergence
roots
quadratics
continued-fractions
When does $\sqrt{x+\sqrt{x+1+\sqrt{x+2+...}}}=0$?
roots
radicals
nested-radicals
How can one find the zeroes of $f(x)=ae^{bx}+cx+d$?
exponential-function
roots
recreational-mathematics
lambert-w
Proof that $\sqrt[m]{a} + \sqrt[n]{b}$ is irrational
roots
irrational-numbers
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