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Proving by strong induction that $\forall n \ge 2, \;\forall d \ge 2 : d \mid n(n+1)(n+2)...(n+d-1) $

Inductive proof of $\,9 \mathrel| 4^n+6n-1\,$ for all $\,n\in\Bbb N$

Prove that $(a-b) \mid (a^n-b^n)$ [duplicate]

Why is this 'Proof' by induction not valid?

Is there no solution to the blue-eyed islander puzzle?

How does backwards induction work to prove a property for all naturals?

Proving $n! > n^3$ for all $n > a$

Simple Proof by induction: $9$ divides $n^3 + (n+1)^3 + (n+2)^3$

Prove by Mathematical Induction: $1(1!) + 2(2!) + \cdot \cdot \cdot +n(n!) = (n+1)!-1$

Proof by induction: $n$th Fibonacci number is at most $ 2^n$

Prove that $1^2+2^2+\cdots+n^2=\frac{n(n+1)(2n+1)}{6}$ for $n \in \mathbb{N}$.

How do I find a flaw in this false proof that $7n = 0$ for all natural numbers?

We all use mathematical induction to prove results, but is there a proof of mathematical induction itself?

Avoiding proof by induction

Prove with induction that $11$ divides $10^{2n}-1$ for all natural numbers.

How can I show that $n! \leqslant \left(\frac{n+1}{2}\right)^n$?

New posts in induction

Strong Mathematical Induction: Why More than One Base Case?

Examples where it is easier to prove more than less

Why doesn't mathematical induction work backwards or with increments other than 1?

Is my game fair?

Proving by strong induction that $\forall n \ge 2, \;\forall d \ge 2 : d \mid n(n+1)(n+2)...(n+d-1) $

Inductive proof of $\,9 \mathrel| 4^n+6n-1\,$ for all $\,n\in\Bbb N$

Prove that $(a-b) \mid (a^n-b^n)$ [duplicate]

Why is this 'Proof' by induction not valid?

Is there no solution to the blue-eyed islander puzzle?

How does backwards induction work to prove a property for all naturals?

Proving $n! > n^3$ for all $n > a$

Simple Proof by induction: $9$ divides $n^3 + (n+1)^3 + (n+2)^3$

Prove by Mathematical Induction: $1(1!) + 2(2!) + \cdot \cdot \cdot +n(n!) = (n+1)!-1$

Proof by induction: $n$th Fibonacci number is at most $ 2^n$

Prove that $1^2+2^2+\cdots+n^2=\frac{n(n+1)(2n+1)}{6}$ for $n \in \mathbb{N}$.

How do I find a flaw in this false proof that $7n = 0$ for all natural numbers?

We all use mathematical induction to prove results, but is there a proof of mathematical induction itself?

Avoiding proof by induction

Prove with induction that $11$ divides $10^{2n}-1$ for all natural numbers.

How can I show that $n! \leqslant \left(\frac{n+1}{2}\right)^n$?