Newbetuts

Treating dy/dx as a symbol for the derivative as opposed to a fraction of the differentials dy and dx

The equation $y'=1+y^4$ blows up in finite time

Find solution to the differential equation : $(2x+1)dx+\frac{x^2-y}{x}dy=0$

Generalizing Archimedes' "The Quadrature of the Parabola"

Solve the PDE: $u_{xx} - 3u_{xt} - 4u_{tt} = 0$ [duplicate]

Algebraic Curves and Second Order Differential Equations

Solution of $ f \circ f=f'$

Find the general solution to 2y''+xy'+y = 0 in the form of a power series about the ordinary point x=0.

Is there a more specific name for this PDE and how do I solve it?

$AB=Y = y + y'(x) (X-x)$ $PG= Y = y - \frac{1}{y'(x)} (X-x)$ Find the curves such that $PM=MG$.

Inverse laplace transform $1/(s^2+9)^2$

How to solve $(y)^{y'}=(y')^{y+c},c \in \mathbb{R}$

Solution for a second order ODE with initial conditions

Physical intuition for the solution to $y' = y$.

New posts in ordinary-differential-equations

Lorenz Attractor, its Geometric Model, and 14th Smale's problem.

Statements on the behavior of solutions to $y' = \sin(xy)$ for large $y(0)$

Grothendieck connections and jets

Does the implicit function theorem imply Peano existence theorem

Sturm-Liouville Questions

Symbol of differential operator transforms like a cotangent vector

Treating dy/dx as a symbol for the derivative as opposed to a fraction of the differentials dy and dx

The equation $y'=1+y^4$ blows up in finite time

Find solution to the differential equation : $(2x+1)dx+\frac{x^2-y}{x}dy=0$

Generalizing Archimedes' "The Quadrature of the Parabola"

Solve the PDE: $u_{xx} - 3u_{xt} - 4u_{tt} = 0$ [duplicate]

Algebraic Curves and Second Order Differential Equations

Solution of $ f \circ f=f'$

Find the general solution to 2y''+xy'+y = 0 in the form of a power series about the ordinary point x=0.

Is there a more specific name for this PDE and how do I solve it?

$AB=Y = y + y'(x) (X-x)$ $PG= Y = y - \frac{1}{y'(x)} (X-x)$ Find the curves such that $PM=MG$.

Inverse laplace transform $1/(s^2+9)^2$

How to solve $(y)^{y'}=(y')^{y+c},c \in \mathbb{R}$

Solution for a second order ODE with initial conditions

Physical intuition for the solution to $y' = y$.