Algebraic Curves and Second Order Differential Equations
Solution 1:
The functions $\sin(x)$ and $\cos(x)$ solve a second-order differential equation, namely $$u'' = -u,$$ and $(\cos(x), \sin(x))$ parametrizes the algebraic curve $x^2 + y^2 = 1$.
Algebraic Curves and Second Order Differential Equations
Solution 1:
The functions $\sin(x)$ and $\cos(x)$ solve a second-order differential equation, namely $$u'' = -u,$$ and $(\cos(x), \sin(x))$ parametrizes the algebraic curve $x^2 + y^2 = 1$.