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New posts in rearrangement-inequality
Proving the inequality $4\ge a^2b+b^2c+c^2a+abc$
inequality
a.m.-g.m.-inequality
rearrangement-inequality
Typical Olympiad Inequality? If $\sum_i^na_i=n$ with $a_i>0$, then $\sum_{i=1}^n\left(\frac{a_i^3+1}{a_i^2+1}\right)^4\geq n$
inequality
contest-math
a.m.-g.m.-inequality
cauchy-schwarz-inequality
rearrangement-inequality
How prove this inequality $x^3y+y^3z+z^3x\ge xyz(x+y+z)$
inequality
polynomials
a.m.-g.m.-inequality
sum-of-squares-method
rearrangement-inequality
Proving $\left(\frac{a}{a+b+c}\right)^2+\left(\frac{b}{b+c+d}\right)^2+\left(\frac{c}{c+d+a}\right)^2+\left(\frac{d}{d+a+b}\right)^2\ge\frac{4}{9}$
inequality
holder-inequality
rearrangement-inequality
tangent-line-method
buffalo-way
Find minimum value of $\sum \frac{\sqrt{a}}{\sqrt{b}+\sqrt{c}-\sqrt{a}}$
inequality
cauchy-schwarz-inequality
geometric-inequalities
jensen-inequality
rearrangement-inequality
Inequality: $ab^2+bc^2+ca^2 \le 4$, when $a+b+c=3$.
inequality
a.m.-g.m.-inequality
rearrangement-inequality
Question involving Inequality [duplicate]
inequality
summation
contest-math
rearrangement-inequality
Prove that $\sqrt{x_1}+\sqrt{x_2}+\cdots+\sqrt{x_n} \geq (n-1) \left (\frac{1}{\sqrt{x_1}}+\frac{1}{\sqrt{x_2}}+\cdots+\frac{1}{\sqrt{x_n}} \right )$
inequality
contest-math
radicals
sum-of-squares-method
rearrangement-inequality
Prove the inequality $\frac{a^8+b^8+c^8}{a^3b^3c^3}\ge\frac{1}{a}+\frac{1}{b}+\frac{1}{c}$ for $a,b,c>0$
inequality
contest-math
rearrangement-inequality
Prove $4(x + y + z)^3 > 27(x^2y + y^2z + z^2x)$
contest-math
rearrangement-inequality
Prove the inequality $a^2bc+b^2cd+c^2da+d^2ab \leq 4$ with $a+b+c+d=4$
inequality
substitution
a.m.-g.m.-inequality
rearrangement-inequality
How prove this inequality $\sum\limits_{cyc}\frac{x+y}{\sqrt{x^2+xy+y^2+yz}}\ge 2+\sqrt{\frac{xy+yz+xz}{x^2+y^2+z^2}}$
inequality
substitution
cauchy-schwarz-inequality
uvw
rearrangement-inequality
If both $a,b>0$, then $a^ab^b \ge a^bb^a$ [closed]
algebra-precalculus
inequality
logarithms
exponentiation
rearrangement-inequality
Proof of the inequality $\frac{a}{b+c}+\frac{b}{a+c}+\frac{c}{a+b} \geq \frac{3}{2}$
inequality
contest-math
cauchy-schwarz-inequality
sum-of-squares-method
rearrangement-inequality
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