How to remove multiple if statements in javascripts

You can remove every if of the code in the following way:

a = [];
b = [];
c = [];
conditions = [
[[a,b,c].every((x) => isEmpty(x)), () => data.refetch()],
[data.isFetching, someOtherFunction],
[response.isFetching, anotherFunction]
];
conditions.forEach(cond => cond[0] && cond[1]());

I would not recommend this as it makes your code less readable and confusing.

Explanation:

The function every will test condition for every element of an array and joining with an and:

...
 [a,b,c].every((x) => isEmpty(x)) 
...

Then to test every condition you can add them to an array and iterate through them, with a callback for every if you want to create:

conditions = [
[[a,b,c].every((x) => isEmpty(x)), () => data.refetch()],
[data.isFetching, someOtherFunction],
[response.isFetching, anotherFunction]
]
condtions.forEach((cond) => { if(cond[0]) cond[1]() } )

Then As suggested by derpirscher you could remove the last if with

conditions.forEach(cond => cond[0] && cond[1]());

But again, this makes your code more confusing, I would suggest keeping the ifs to make it more clear.