Using an array as needles in strpos

@Dave an updated snippet from http://www.php.net/manual/en/function.strpos.php#107351

function strposa($haystack, $needles=array(), $offset=0) {
        $chr = array();
        foreach($needles as $needle) {
                $res = strpos($haystack, $needle, $offset);
                if ($res !== false) $chr[$needle] = $res;
        }
        if(empty($chr)) return false;
        return min($chr);
}

How to use:

$string = 'Whis string contains word "cheese" and "tea".';
$array  = array('burger', 'melon', 'cheese', 'milk');

if (strposa($string, $array, 1)) {
    echo 'true';
} else {
    echo 'false';
}

will return true, because of array "cheese".

Update: Improved code with stop when the first of the needles is found:

function strposa(string $haystack, array $needles, int $offset = 0): bool 
{
    foreach($needles as $needle) {
        if(strpos($haystack, $query, $offset) !== false) {
            return true; // stop on first true result
        }
    }

    return false;
}
$string = 'This string contains word "cheese" and "tea".';
$array  = ['burger', 'melon', 'cheese', 'milk'];
var_dump(strposa($string, $array)); // will return true, since "cheese" has been found

str_replace is considerably faster.

$find_letters = array('a', 'c', 'd');
$string = 'abcdefg';
$match = (str_replace($find_letters, '', $string) != $string);

The below code not only shows how to do it, but also puts it in an easy to use function moving forward. It was written by "jesda". (I found it online)

PHP Code:

<?php
/* strpos that takes an array of values to match against a string
 * note the stupid argument order (to match strpos)
 */
function strpos_arr($haystack, $needle) {
    if(!is_array($needle)) $needle = array($needle);
    foreach($needle as $what) {
        if(($pos = strpos($haystack, $what))!==false) return $pos;
    }
    return false;
}
?>

Usage:

$needle = array('something','nothing');
$haystack = "This is something";
echo strpos_arr($haystack, $needle); // Will echo True

$haystack = "This isn't anything";
echo strpos_arr($haystack, $needle); // Will echo False

The question, is the provided example just an "example" or exact what you looking for? There are many mixed answers here, and I dont understand the complexibility of the accepted one.

To find out if ANY content of the array of needles exists in the string, and quickly return true or false:

$string = 'abcdefg';

if(str_replace(array('a', 'c', 'd'), '', $string) != $string){
    echo 'at least one of the needles where found';
};

If, so, please give @Leon credit for that.

To find out if ALL values of the array of needles exists in the string, as in this case, all three 'a', 'b' and 'c' MUST be present, like you mention as your "for example"

echo 'All the letters are found in the string!';

Many answers here is out of that context, but I doubt that the intension of the question as you marked as resolved. E.g. The accepted answer is a needle of

$array  = array('burger', 'melon', 'cheese', 'milk');

What if all those words MUST be found in the string?

Then you try out some "not accepted answers" on this page.

You can iterate through the array and set a "flag" value if strpos returns false.

$flag = false;
foreach ($find_letters as $letter)
{
    if (strpos($string, $letter) === false)
    {
        $flag = true;
    }
}

Then check the value of $flag.

Using an array as needles in strpos

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