How do I do a HTTP GET in Java? [duplicate]
How do I do a HTTP GET in Java?
Solution 1:
If you want to stream any webpage, you can use the method below.
import java.io.*;
import java.net.*;
public class c {
public static String getHTML(String urlToRead) throws Exception {
StringBuilder result = new StringBuilder();
URL url = new URL(urlToRead);
HttpURLConnection conn = (HttpURLConnection) url.openConnection();
conn.setRequestMethod("GET");
try (BufferedReader reader = new BufferedReader(
new InputStreamReader(conn.getInputStream()))) {
for (String line; (line = reader.readLine()) != null; ) {
result.append(line);
}
}
return result.toString();
}
public static void main(String[] args) throws Exception
{
System.out.println(getHTML(args[0]));
}
}
Solution 2:
Technically you could do it with a straight TCP socket. I wouldn't recommend it however. I would highly recommend you use Apache HttpClient instead. In its simplest form:
GetMethod get = new GetMethod("http://httpcomponents.apache.org");
// execute method and handle any error responses.
...
InputStream in = get.getResponseBodyAsStream();
// Process the data from the input stream.
get.releaseConnection();
and here is a more complete example.
Solution 3:
If you dont want to use external libraries, you can use URL and URLConnection classes from standard Java API.
An example looks like this:
String urlString = "http://wherever.com/someAction?param1=value1¶m2=value2....";
URL url = new URL(urlString);
URLConnection conn = url.openConnection();
InputStream is = conn.getInputStream();
// Do what you want with that stream
Solution 4:
The simplest way that doesn't require third party libraries it to create a URL object and then call either openConnection or openStream on it. Note that this is a pretty basic API, so you won't have a lot of control over the headers.