How to parse strings to look like sys.argv
I believe you want the shlex module.
>>> import shlex
>>> shlex.split('-o 1 --long "Some long string"')
['-o', '1', '--long', 'Some long string']
Before I was aware of shlex.split
, I made the following:
import sys
_WORD_DIVIDERS = set((' ', '\t', '\r', '\n'))
_QUOTE_CHARS_DICT = {
'\\': '\\',
' ': ' ',
'"': '"',
'r': '\r',
'n': '\n',
't': '\t',
}
def _raise_type_error():
raise TypeError("Bytes must be decoded to Unicode first")
def parse_to_argv_gen(instring):
is_in_quotes = False
instring_iter = iter(instring)
join_string = instring[0:0]
c_list = []
c = ' '
while True:
# Skip whitespace
try:
while True:
if not isinstance(c, str) and sys.version_info[0] >= 3:
_raise_type_error()
if c not in _WORD_DIVIDERS:
break
c = next(instring_iter)
except StopIteration:
break
# Read word
try:
while True:
if not isinstance(c, str) and sys.version_info[0] >= 3:
_raise_type_error()
if not is_in_quotes and c in _WORD_DIVIDERS:
break
if c == '"':
is_in_quotes = not is_in_quotes
c = None
elif c == '\\':
c = next(instring_iter)
c = _QUOTE_CHARS_DICT.get(c)
if c is not None:
c_list.append(c)
c = next(instring_iter)
yield join_string.join(c_list)
c_list = []
except StopIteration:
yield join_string.join(c_list)
break
def parse_to_argv(instring):
return list(parse_to_argv_gen(instring))
This works with Python 2.x and 3.x. On Python 2.x, it works directly with byte strings and Unicode strings. On Python 3.x, it only accepts [Unicode] strings, not bytes
objects.
This doesn't behave exactly the same as shell argv splitting—it also allows quoting of CR, LF and TAB characters as \r
, \n
and \t
, converting them to real CR, LF, TAB (shlex.split
doesn't do that). So writing my own function was useful for my needs. I guess shlex.split
is better if you just want plain shell-style argv splitting. I'm sharing this code in case it's useful as a baseline for doing something slightly different.