C++ pure virtual const member function

From Microsoft Docs:

To declare a constant member function, place the const keyword after the closing parenthesis of the argument list.

So it should be:

virtual void print() const = 0;

Only the virtual void print() const = 0 form is acceptable. Take a look at the grammar specification in C++03 §9/2:

member-declarator:
    declarator pure-specifier_opt
    declarator constant-initializer_opt
    identifier_opt : constant-expression

pure-specifier:
    = 0

The const is part of the declarator -- it's the cv-qualifier-seq_opt in the direct-declarator (§8/4):

declarator:
    direct-declarator
    ptr-operator *declarator*

direct-declarator:
    declarator-id
    direct-declarator ( parameter-declaration-clause ) cv-qualifier-seq_opt exception-specification_opt
    direct-declarator [ constant-expression_opt ]
    ( declarator )

Hence, the = 0 must come after the const.

Of course you can. The correct syntax is:

virtual void print() const = 0;