Find duplicate records in MySQL

I want to pull out duplicate records in a MySQL Database. This can be done with:

SELECT address, count(id) as cnt FROM list
GROUP BY address HAVING cnt > 1

Which results in:

100 MAIN ST    2

I would like to pull it so that it shows each row that is a duplicate. Something like:

JIM    JONES    100 MAIN ST
JOHN   SMITH    100 MAIN ST

Any thoughts on how this can be done? I'm trying to avoid doing the first one then looking up the duplicates with a second query in the code.

Solution 1:

The key is to rewrite this query so that it can be used as a subquery.

SELECT firstname, 
   lastname, 
   list.address 
FROM list
   INNER JOIN (SELECT address
               FROM   list
               GROUP  BY address
               HAVING COUNT(id) > 1) dup
           ON list.address = dup.address;

Solution 2:

SELECT date FROM logs group by date having count(*) >= 2

Solution 3:

Why not just INNER JOIN the table with itself?

SELECT a.firstname, a.lastname, a.address
FROM list a
INNER JOIN list b ON a.address = b.address
WHERE a.id <> b.id

A DISTINCT is needed if the address could exist more than two times.

Solution 4:

I tried the best answer chosen for this question, but it confused me somewhat. I actually needed that just on a single field from my table. The following example from this link worked out very well for me:

SELECT COUNT(*) c,title FROM `data` GROUP BY title HAVING c > 1;

Solution 5:

select `cityname` from `codcities` group by `cityname` having count(*)>=2

This is the similar query you have asked for and its 200% working and easy too. Enjoy!!!