ZFS: Does anyone know how to roll a zvol back in time?
Solution 1:
Yes, it can be done. It will be messy.
https://gist.github.com/jshoward/5685757
Including the original file now that the link has gone dead.
zfs_revert-0.1.py
#!/usr/bin/python
# -*- coding: utf-8 -*-
#Script for reverting ZFS changes by destroying uberblocks
#Author: Martin Vool
#E-mail: [email protected]
#Version: 0.1
#Date: 16 November 2009
import time
import subprocess
import sys
import os
#Default blocksize
bs=512
#default total blocks (sorry programming in estonian :-/)
suurus=None
if len(sys.argv) > 2:
for arg in sys.argv:
arg=arg.split('=')
if len(arg) == 1:
file=arg[0]
elif arg[0] == '-bs':
bs=int(arg[1])
elif arg[0] == '-tb':
suurus=int(arg[1])
else:
print 'Usage: zfs_revert.py [-bs=n default:n=512 blocksize] \\n [-tb=n total block size in blocks] [file/device] You have to set -tb'
exit(1)
print int(bs)
if suurus == None:
print 'Total block size in blocks is undefined'
exit(1)
#make solaris use gnu grep.
if os.uname()[0] == 'SunOS':
grep_cmd='ggrep'
else:
grep_cmd='grep'
#to format program output
def formatstd(inp):
inp=inp.split('\n')
ret=[]
for line in inp:
columns=line.split(' ')
nc=[]
for c in columns:
if c != '':
nc.append(c)
ret.append(nc)
return ret
#read blocks from beginning(64mb)
a_count=(256*bs)
#read blocks from end (64mb)
l_skip=suurus-(256*bs)
print 'Total of %s blocks'%suurus
print 'Reading from the beginning to %s blocks'%a_count
print 'Reading from %s blocks to the end'%l_skip
#get the uberblocks from the beginning and end
yberblocks_a=formatstd(subprocess.Popen('sync && dd bs=%s if=%s count=%s | od -A x -x | %s -A 2 "b10c 00ba" | %s -v "\-\-"'%(bs,file, a_count,grep_cmd,grep_cmd), shell=True, stdout=subprocess.PIPE).communicate()[0])
yberblocks_l=formatstd(subprocess.Popen('sync && dd bs=%s if=%s skip=%s | od -A x -x | %s -A 2 "b10c 00ba" | %s -v "\-\-"'%(bs,file, l_skip,grep_cmd,grep_cmd), shell=True, stdout=subprocess.PIPE).communicate()[0])
yberblocks=[]
for p in yberblocks_a:
if len(p) > 0:
#format the hex address to decmal so dd would eat it.
p[0]=(int(p[0], 16)/bs)
yberblocks.append(p)
for p in yberblocks_l:
if len(p) > 0:
#format the hex address to decmal so dd would eat it and add the skipped part.
p[0]=((int(p[0], 16)/bs)+int(l_skip)) #we have to add until the place we skipped so the adresses would mach.
yberblocks.append(p)
print '----'
#here will be kept the output that you will see later(TXG, timestamp and the adresses, should be 4, might be less)
koik={}
i=0
for p in yberblocks:
if len(p) > 0:
if i == 0:#the first output line
address=p[0]
elif i == 1:#second output line
#this is the output of od that is in hex and needs to be reversed
txg=int(p[4]+p[3]+p[2]+p[1], 16)
elif i == 2:#third output line
timestamp=int(p[4]+p[3]+p[2]+p[1], 16)
try:
aeg=time.strftime("%d %b %Y %H:%M:%S", time.localtime(timestamp))
except:
aeg='none'
if koik.has_key(txg):
koik[txg]['addresses'].append(address)
else:
koik[txg]={
'txg':txg,
'timestamp':timestamp,
'htime': aeg,
'addresses':[address]
}
if i == 2:
i=0
else:
i+=1
keys = koik.keys()
keys.sort()
while True:
keys = koik.keys()
keys.sort()
print 'TXG\tTIME\tTIMESTAMP\tBLOCK ADDRESSES'
for k in keys:
print '%s\t%s\t%s\t%s'%(k, koik[k]['htime'],koik[k]['timestamp'],koik[k]['addresses'])
try:
save_txg=int(input('What is the last TXG you wish to keep?\n'))
keys = koik.keys()
keys.sort()
for k in keys:
if k > save_txg:
for adress in koik[k]['addresses']:
#wrtie zeroes to the unwanted uberblocks
format=formatstd(subprocess.Popen('dd bs=%s if=/dev/zero of=%s seek=%s count=1 conv=notrunc'%(bs, file, adress), shell=True, stdout=subprocess.PIPE).communicate()[0])
del(koik[k])
#sync changes to disc!
sync=formatstd(subprocess.Popen('sync', shell=True, stdout=subprocess.PIPE).communicate()[0])
except:
print ''
break
Solution 2:
There isn't a relevant snapshot; I figured that went without saying.
So, without a snapshot that correlates with a time where the zpool and data are healthy, you don't have any easy recourse or ability to roll back.