Converting date between DD/MM/YYYY and YYYY-MM-DD?

Using a Python script, I need to read a CVS file where dates are formated as DD/MM/YYYY, and convert them to YYYY-MM-DD before saving this into a SQLite database.

This almost works, but fails because I don't provide time:

from datetime import datetime

lastconnection = datetime.strptime("21/12/2008", "%Y-%m-%d")

#ValueError: time data did not match format:  data=21/12/2008  fmt=%Y-%m-%d
print lastconnection

I assume there's a method in the datetime object to perform this conversion very easily, but I can't find an example of how to do it. Thank you.

Your example code is wrong. This works:

import datetime

datetime.datetime.strptime("21/12/2008", "%d/%m/%Y").strftime("%Y-%m-%d")

The call to strptime() parses the first argument according to the format specified in the second, so those two need to match. Then you can call strftime() to format the result into the desired final format.

you first would need to convert string into datetime tuple, and then convert that datetime tuple to string, it would go like this:

lastconnection = datetime.strptime("21/12/2008", "%d/%m/%Y").strftime('%Y-%m-%d')

I am new to programming. I wanted to convert from yyyy-mm-dd to dd/mm/yyyy to print out a date in the format that people in my part of the world use and recognise.

The accepted answer above got me on the right track.

The answer I ended up with to my problem is:

import datetime

today_date = datetime.date.today()
print(today_date)

new_today_date = today_date.strftime("%d/%m/%Y")
print (new_today_date)

The first two lines after the import statement gives today's date in the USA format (2017-01-26). The last two lines convert this to the format recognised in the UK and other countries (26/01/2017).

You can shorten this code, but I left it as is because it is helpful to me as a beginner. I hope this helps other beginner programmers starting out!