String concatenation in Java - when to use +, StringBuilder and concat [duplicate]
Solution 1:
Modern Java compiler convert your + operations by StringBuilder's append. I mean to say if you do str = str1 + str2 + str3
then the compiler will generate the following code:
StringBuilder sb = new StringBuilder();
str = sb.append(str1).append(str2).append(str3).toString();
You can decompile code using DJ or Cavaj to confirm this :) So now its more a matter of choice than performance benefit to use + or StringBuilder :)
However given the situation that compiler does not do it for your (if you are using any private Java SDK to do it then it may happen), then surely StringBuilder is the way to go as you end up avoiding lots of unnecessary String
objects.
Solution 2:
I tend to use StringBuilder
on code paths where performance is a concern. Repeated string concatenation within a loop is often a good candidate.
The reason to prefer StringBuilder
is that both +
and concat
create a new object every time you call them (provided the right hand side argument is not empty). This can quickly add up to a lot of objects, almost all of which are completely unnecessary.
As others have pointed out, when you use +
multiple times within the same statement, the compiler can often optimize this for you. However, in my experience this argument doesn't apply when the concatenations happen in separate statements. It certainly doesn't help with loops.
Having said all this, I think top priority should be writing clear code. There are some great profiling tools available for Java (I use YourKit), which make it very easy to pinpoint performance bottlenecks and optimize just the bits where it matters.
P.S. I have never needed to use concat
.
Solution 3:
From Java/J2EE Job Interview Companion:
String
String
is immutable: you can’t modify aString
object but can replace it by creating a new instance. Creating a new instance is rather expensive.//Inefficient version using immutable String String output = "Some text"; int count = 100; for (int i = 0; i < count; i++) { output += i; } return output;
The above code would build 99 new
String
objects, of which 98 would be thrown away immediately. Creating new objects is not efficient.
StringBuffer
/StringBuilder
StringBuffer
is mutable: useStringBuffer
orStringBuilder
when you want to modify the contents.StringBuilder
was added in Java 5 and it is identical in all respects toStringBuffer
except that it is not synchronised, which makes it slightly faster at the cost of not being thread-safe.//More efficient version using mutable StringBuffer StringBuffer output = new StringBuffer(110); output.append("Some text"); for (int i = 0; i < count; i++) { output.append(i); } return output.toString();
The above code creates only two new objects, the
StringBuffer
and the finalString
that is returned.StringBuffer
expands as needed, which is costly however, so it would be better to initialise theStringBuffer
with the correct size from the start as shown.
Solution 4:
If all concatenated elements are constants (example : "these" + "are" + "constants"
), then I'd prefer the +, because the compiler will inline the concatenation for you. Otherwise, using StringBuilder is the most effective way.
If you use + with non-constants, the Compiler will internally use StringBuilder as well, but debugging becomes hell, because the code used is no longer identical to your source code.
Solution 5:
My recommendation would be as follows:
-
+
: Use when concatenating 2 or 3 Strings simply to keep your code brief and readable. -
StringBuilder
: Use when building up complex String output or where performance is a concern. -
String.format
: You didn't mention this in your question but it is my preferred method for creating Strings as it keeps the code the most readable / concise in my opinion and is particularly useful for log statements. -
concat
: I don't think I've ever had cause to use this.