Is there a better way to have optional function arguments in Haskell?
I'm used to being able to define optional arguments like so in Python:
def product(a, b=2):
return a * b
Haskell doesn't have default arguments, but I was able to get something similar by using a Maybe:
product a (Just b) = a * b
product a Nothing = a * 2
This becomes cumbersome very quickly if you have more than multiple parameters though. For example, what if I want to do something like this:
def multiProduct (a, b=10, c=20, d=30):
return a * b * c * d
I would have to have eight definitions of multiProduct to account for all cases.
Instead, I decided to go with this:
multiProduct req1 opt1 opt2 opt3 = req1 * opt1' * opt2' * opt3'
where opt1' = if isJust opt1 then (fromJust opt1) else 10
where opt2' = if isJust opt2 then (fromJust opt2) else 20
where opt3' = if isJust opt3 then (fromJust opt3) else 30
That looks very inelegant to me. Is there an idiomatic way to do this in Haskell that is cleaner?
Solution 1:
Perhaps some nice notation would be easier on the eyes:
(//) :: Maybe a -> a -> a
Just x // _ = x
Nothing // y = y
-- basically fromMaybe, just want to be transparent
multiProduct req1 opt1 opt2 opt3 = req1 * (opt1 // 10) * (opt2 // 20) * (opt3 // 30)
If you need to use the parameters more than once, I suggest going with @pat's method.
EDIT 6 years later
With ViewPatterns
you can put the defaults on the left.
{-# LANGUAGE ViewPatterns #-}
import Data.Maybe (fromMaybe)
def :: a -> Maybe a -> a
def = fromMaybe
multiProduct :: Int -> Maybe Int -> Maybe Int -> Maybe Int -> Int
multiProduct req1 (def 10 -> opt1) (def 20 -> opt2) (def 30 -> opt3)
= req1 * opt1 * opt2 * opt3
Solution 2:
Here's yet another way to do optional arguments in Haskell:
{-# LANGUAGE MultiParamTypeClasses, FlexibleInstances, FlexibleContexts #-}
module Optional where
class Optional1 a b r where
opt1 :: (a -> b) -> a -> r
instance Optional1 a b b where
opt1 = id
instance Optional1 a b (a -> b) where
opt1 = const
class Optional2 a b c r where
opt2 :: (a -> b -> c) -> a -> b -> r
instance Optional2 a b c c where
opt2 = id
instance (Optional1 b c r) => Optional2 a b c (a -> r) where
opt2 f _ b = \a -> opt1 (f a) b
{- Optional3, Optional4, etc defined similarly -}
Then
{-# LANGUAGE FlexibleContexts #-}
module Main where
import Optional
foo :: (Optional2 Int Char String r) => r
foo = opt2 replicate 3 'f'
_5 :: Int
_5 = 5
main = do
putStrLn $ foo -- prints "fff"
putStrLn $ foo _5 -- prints "fffff"
putStrLn $ foo _5 'y' -- prints "yyyyy"
Update: Whoops, I got accepted. I honestly think that luqui's answer is the best one here:
- the type is clear, and easy to read, even for beginners
- same for type errors
- GHC doesn't need hints to do type inference with it (try
opt2 replicate 3 'f'
in ghci to see what I mean) - the optional arguments are order-independent
Solution 3:
I don't know of a better way to solve the underlying problem, but your example can be written more succinctly as:
multiProduct req1 opt1 opt2 opt3 = req1 * opt1' * opt2' * opt3'
where opt1' = fromMaybe 10 opt1
opt2' = fromMaybe 20 opt2
opt3' = fromMaybe 30 opt3
Solution 4:
When arguments get too complex, one solution is to create a data type just for the arguments. Then you can create a default constructor for that type, and fill in only what you want to replace in your function calls.
Example:
$ runhaskell dog.hs
Snoopy (Beagle): Ruff!
Snoopy (Beagle): Ruff!
Wishbone (Terrier): Ruff!
Wishbone (Terrier): Ruff!
Wishbone (Terrier): Ruff!
dog.hs:
#!/usr/bin/env runhaskell
import Control.Monad (replicateM_)
data Dog = Dog {
name :: String,
breed :: String,
barks :: Int
}
defaultDog :: Dog
defaultDog = Dog {
name = "Dog",
breed = "Beagle",
barks = 2
}
bark :: Dog -> IO ()
bark dog = replicateM_ (barks dog) $ putStrLn $ (name dog) ++ " (" ++ (breed dog) ++ "): Ruff!"
main :: IO ()
main = do
bark $ defaultDog {
name = "Snoopy",
barks = 2
}
bark $ defaultDog {
name = "Wishbone",
breed = "Terrier",
barks = 3
}