Validate presence of field only if another field is blank - Rails

You don't need a lambda. This will do:

validates_presence_of :mobile_number, :unless => :home_phone?

Also, all of the validators take the same if/unless options, so you can make them conditional at will.

Update: Looking back at this answer a few days later, I see that I should explain why it works:

• If you set a validator's :unless option to be a symbol, Rails will look for an instance method of that name, invoke that method on the instance that's being validated -- at validation time -- and only perform the validation if the method returns false.
• ActiveRecord automatically creates question mark methods for each of your model's attributes, so the existence of a home_phone column in your model's table causes Rails to create a handy #home_phone? method. This method returns true if and only if home_phone is present (i.e. not blank). If the home_phone attribute is nil or an empty string or a bunch of white space, home_phone? will return false.

UPDATE: Confirmed that this old technique continues to work in Rails 5.

You must use a lambda / Proc object:

validates_presence_of :mobile_number, :unless => lambda { self.home_phone.blank? }

Starting in Rails 4, you can pass a block to presence. Concisely:

validates :mobile_number, presence: {unless: :home_phone?}

Also, :home_phone? returns false for nil or blank.

Here is another way that works in rails 4

  validates_presence_of :job, if: :executed_at?

  validates :code,
            presence: true,
            length:  { minimum: 10, maximum: 50 },
            uniqueness: { case_sensitive: false },
            numericality: { only_integer: true }

a short solution:

validates_presence_of :mobile_number, unless: -> { home_phone.blank? }