Sort a single String in Java
toCharArray
followed by Arrays.sort
followed by a String constructor call:
import java.util.Arrays;
public class Test
{
public static void main(String[] args)
{
String original = "edcba";
char[] chars = original.toCharArray();
Arrays.sort(chars);
String sorted = new String(chars);
System.out.println(sorted);
}
}
EDIT: As tackline points out, this will fail if the string contains surrogate pairs or indeed composite characters (accent + e as separate chars) etc. At that point it gets a lot harder... hopefully you don't need this :) In addition, this is just ordering by ordinal, without taking capitalisation, accents or anything else into account.
No there is no built-in String method. You can convert it to a char array, sort it using Arrays.sort and convert that back into a String.
String test= "edcba";
char[] ar = test.toCharArray();
Arrays.sort(ar);
String sorted = String.valueOf(ar);
Or, when you want to deal correctly with locale-specific stuff like uppercase and accented characters:
import java.text.Collator;
import java.util.Arrays;
import java.util.Comparator;
import java.util.Locale;
public class Test
{
public static void main(String[] args)
{
Collator collator = Collator.getInstance(new Locale("fr", "FR"));
String original = "éDedCBcbAàa";
String[] split = original.split("");
Arrays.sort(split, collator);
String sorted = "";
for (int i = 0; i < split.length; i++)
{
sorted += split[i];
}
System.out.println(sorted); // "aAàbBcCdDeé"
}
}
In Java 8 it can be done with:
String s = "edcba".chars()
.sorted()
.collect(StringBuilder::new, StringBuilder::appendCodePoint, StringBuilder::append)
.toString();
A slightly shorter alternative that works with a Stream of Strings of length one (each character in the unsorted String is converted into a String in the Stream) is:
String sorted =
Stream.of("edcba".split(""))
.sorted()
.collect(Collectors.joining());
Convert to array of chars → Sort → Convert back to String:
String s = "edcba";
char[] c = s.toCharArray(); // convert to array of chars
java.util.Arrays.sort(c); // sort
String newString = new String(c); // convert back to String
System.out.println(newString); // "abcde"