call printf using va_list

void TestPrint(char* format, ...)
{
    va_list argList;

    va_start(argList, format);
    printf(format, argList);
    va_end(argList);
}


int main()
{
    TestPrint("Test print %s %d\n", "string", 55);
    return 0;
}

I need to get:

Test print string 55

Actually, I get garbage output. What is wrong in this code?

Use vprintf() instead.

Instead of printf, I recommend you try vprintf instead, which was created for this specific purpose:

#include <stdio.h>
#include <stdlib.h>
#include <stdarg.h>

void errmsg( const char* format, ... )
{
    va_list arglist;

    printf( "Error: " );
    va_start( arglist, format );
    vprintf( format, arglist );
    va_end( arglist );
}

int main( void )
{
    errmsg( "%s %d %s", "Failed", 100, "times" );
    return EXIT_SUCCESS;
}

Source