How to define string literal union type from constants in Typescript

I know I can define string union types to restrict variables to one of the possible string values:

type MyType = 'first' | 'second'
let myVar:MyType = 'first'

I need to construct a type like that from constant strings, e.g:

const MY_CONSTANT = 'MY_CONSTANT'
const SOMETHING_ELSE = 'SOMETHING_ELSE'
type MyType = MY_CONSTANT | SOMETHING_ELSE

But for some reason it doesn't work; it says MY_CONSTANT refers to a value, but it being used as a type here.

Why does Typescript allow the first example, but doesn't allow the second case? I'm on Typescript 3.4.5

To get the type of a variable you need to use the typeof type operator:

const MY_CONSTANT = 'MY_CONSTANT' // must be const, no annotation. let or var will not work
const SOMETHING_ELSE = 'SOMETHING_ELSE' // must be const, no annotation. let or var will not work
type MyType = typeof MY_CONSTANT | typeof SOMETHING_ELSE

Playground

Note:

Since there seems to be a lot of confusion when people use this. The const matters. If you use other types of declarations (let or var) the final type would be string. Only const preserves string literal types.

Note 2:

For this solution to work you must not specify any type annotation on the const, and let the compiler infer the type of the constants (ex this will not work :const MY_CONSTANT: string = 'MY_CONSTANT')

You can also use enum for this case. For example:

// Define enum.
enum myConstants {
  MY_CONSTANT = 'my_constant',
  SMTH_ELSE = 'smth_else'
}

// Use it in an interface for typechecking.
interface MyInterface {
  myProp: myConstants
}

// Example of correct object - no errors.
let a: MyInterface = {
  myProp: myConstants.MY_CONSTANT
}

// Incorrect value - TS reports an error.
let b: MyInterface = {
  myProp: 'John Doe'
}

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