Divisibility question from a very old textbook.
$$ 10^5 \equiv 1 \pmod {41} $$ $$ 9+8+7+6+5+4+2 = 41 $$
Divisibility question from a very old textbook.
$$ 10^5 \equiv 1 \pmod {41} $$ $$ 9+8+7+6+5+4+2 = 41 $$
$$ 10^5 \equiv 1 \pmod {41} $$ $$ 9+8+7+6+5+4+2 = 41 $$