How to know if the running platform is Ubuntu or CentOS with help of a Bash script?
Solution 1:
Unfortunately, there is no surefire, simple way of getting the distribution name. Most major distros are moving towards a system where they use /etc/os-release
to store this information. Most modern distributions also include the lsb_release
tools but these are not always installed by default. So, here are some approaches you can use:
-
Use
/etc/os-release
awk -F= '/^NAME/{print $2}' /etc/os-release
-
Use the
lsb_release
tools if availablelsb_release -d | awk -F"\t" '{print $2}'
-
Use a more complex script that should work for the great majority of distros:
# Determine OS platform UNAME=$(uname | tr "[:upper:]" "[:lower:]") # If Linux, try to determine specific distribution if [ "$UNAME" == "linux" ]; then # If available, use LSB to identify distribution if [ -f /etc/lsb-release -o -d /etc/lsb-release.d ]; then export DISTRO=$(lsb_release -i | cut -d: -f2 | sed s/'^\t'//) # Otherwise, use release info file else export DISTRO=$(ls -d /etc/[A-Za-z]*[_-][rv]e[lr]* | grep -v "lsb" | cut -d'/' -f3 | cut -d'-' -f1 | cut -d'_' -f1) fi fi # For everything else (or if above failed), just use generic identifier [ "$DISTRO" == "" ] && export DISTRO=$UNAME unset UNAME
-
Parse the version info of
gcc
if installed:CentOS 5.x
$ gcc --version gcc (GCC) 4.1.2 20080704 (Red Hat 4.1.2-54) Copyright (C) 2006 Free Software Foundation, Inc.
CentOS 6.x
$ gcc --version gcc (GCC) 4.4.7 20120313 (Red Hat 4.4.7-3) Copyright (C) 2010 Free Software Foundation, Inc.
Ubuntu 12.04
$ gcc --version gcc (Ubuntu/Linaro 4.6.3-1ubuntu5) 4.6.3 Copyright (C) 2011 Free Software Foundation, Inc.
Ubuntu 14.04
$ gcc --version gcc (Ubuntu 4.8.2-19ubuntu1) 4.8.2 Copyright (C) 2013 Free Software Foundation, Inc. This is free software; see the source for copying conditions. There is NO warranty; not even for MERCHANTABILITY or FITNESS FOR A PARTICULAR PURPOSE.
This has basically been directly copied from @slm's great answer to my question here.
Solution 2:
You don't need bash to do such task, and I'd suggest using a high-level approach to avoid dealing with files like /etc/version
and /etc/issue
(I don't have /etc/version on 13.10).
So my recommendation is to use this command instead:
python -mplatform | grep -qi Ubuntu && sudo apt-get update || sudo yum update
python platform module will work on both systems, the rest of the command will check if Ubuntu is returned by python and run apt-get
else yum
.
Solution 3:
Here's a simple answer that I find works across all versions of Ubuntu / CentOS / RHEL by the mere presence of the files (not failsafe of course if someone is randomly dropping /etc/redhat-release on your Ubuntu boxes, etc):
if [ -f /etc/redhat-release ]; then
yum update
fi
if [ -f /etc/lsb-release ]; then
apt-get update
fi
Solution 4:
Check for Ubuntu in the kernel name:
if [ -n "$(uname -a | grep Ubuntu)" ]; then
sudo apt-get update && sudo apt-get upgrade
else
yum update
fi