Benefits of ternary operator vs. if statement
Solution 1:
Performance
The ternary operator shouldn't differ in performance from a well-written equivalent if
/else
statement... they may well resolve to the same representation in the Abstract Syntax Tree, undergo the same optimisations etc..
Things you can only do with ? :
If you're initialising a constant or reference, or working out which value to use inside a member initialisation list, then if
/else
statements can't be used but ?
:
can be:
const int x = f() ? 10 : 2;
X::X() : n_(n > 0 ? 2 * n : 0) { }
Factoring for concise code
Keys reasons to use ?
:
include localisation, and avoiding redundantly repeating other parts of the same statements/function-calls, for example:
if (condition)
return x;
else
return y;
...is only preferable to...
return condition ? x : y;
...on readability grounds if dealing with very inexperienced programmers, or some of the terms are complicated enough that the ?
:
structure gets lost in the noise. In more complex cases like:
fn(condition1 ? t1 : f1, condition2 ? t2 : f2, condition3 ? t3 : f3);
An equivalent if
/else
:
if (condition1)
if (condition2)
if (condition3)
fn(t1, t2, t3);
else
fn(t1, t2, f3);
else if (condition3)
fn(t1, f2, t3);
else
fn(t1, f2, f3);
else
if (condition2)
...etc...
That's a lot of extra function calls that the compiler may or may not optimise away.
Further, ?
allows you to select an object, then use a member thereof:
(f() ? a : b).fn(g() ? c : d).field_name);
The equivalent if
/else
would be:
if (f())
if (g())
x.fn(c.field_name);
else
x.fn(d.field_name);
else
if (g())
y.fn(c.field_name);
else
y.fn(d.field_name);
Can't named temporaries improve the if/else monstrosity above?
If the expressions t1
, f1
, t2
etc. are too verbose to type repeatedly, creating named temporaries may help, but then:
To get performance matching
?
:
you may need to usestd::move
, except when the same temporary is passed to two&&
parameters in the function called: then you must avoid it. That's more complex and error-prone.c
?
x:
y evaluates c then either but not both of x and y, which makes it safe to say test a pointer isn'tnullptr
before using it, while providing some fallback value/behaviour. The code only gets the side effects of whichever of x and y is actually selected. With named temporaries, you may needif
/else
around or?
:
inside their initialisation to prevent unwanted code executing, or code executing more often than desired.
Functional difference: unifying result type
Consider:
void is(int) { std::cout << "int\n"; }
void is(double) { std::cout << "double\n"; }
void f(bool expr)
{
is(expr ? 1 : 2.0);
if (expr)
is(1);
else
is(2.0);
}
In the conditional operator version above, 1
undergoes a Standard Conversion to double
so that the type matched 2.0
, meaning the is(double)
overload is called even for the true
/1
situation. The if
/else
statement doesn't trigger this conversion: the true
/1
branch calls is(int)
.
You can't use expressions with an overall type of void
in a conditional operator either, whereas they're valid in statements under an if
/else
.
Emphasis: value-selection before/after action needing values
There's a different emphasis:
An if
/else
statement emphasises the branching first and what's to be done is secondary, while a ternary operator emphasises what's to be done over the selection of the values to do it with.
In different situations, either may better reflect the programmer's "natural" perspective on the code and make it easier to understand, verify and maintain. You may find yourself selecting one over the other based on the order in which you consider these factors when writing the code - if you've launched into "doing something" then find you might use one of a couple (or few) values to do it with, ?
:
is the least disruptive way to express that and continue your coding "flow".
Solution 2:
The only potential benefit to ternary operators over plain if statements in my view is their ability to be used for initializations, which is particularly useful for const
:
E.g.
const int foo = (a > b ? b : a - 10);
Doing this with an if/else block is impossible without using a function cal as well. If you happen to have lots of cases of const things like this you might find there's a small gain from initializing a const properly over assignment with if/else. Measure it! Probably won't even be measurable though. The reason I tend to do this is because by marking it const the compiler knows when I do something later that could/would accidentally change something I thought was fixed.
Effectively what I'm saying is that ternary operator is important for const-correctness, and const correctness is a great habit to be in:
- This saves a lot of your time by letting the compiler help you spot mistakes you make
- This can potentially let the compiler apply other optimizations
Solution 3:
Well...
I did a few tests with GCC and this function call:
add(argc, (argc > 1)?(argv[1][0] > 5)?50:10:1, (argc > 2)?(argv[2][0] > 5)?50:10:1, (argc > 3)?(argv[3][0] > 5)?50:10:1);
The resulting assembler code with gcc -O3 had 35 instructions.
The equivalent code with if/else + intermediate variables had 36. With nested if/else using the fact that 3 > 2 > 1, I got 44. I did not even try to expand this into separate function calls.
Now I did not do any performance analysis, nor did I do a quality check of the resulting assembler code, but at something simple like this with no loops e.t.c. I believe shorter is better.
It appears that there is some value to ternary operators after all :-)
That is only if code speed is absolutely crucial, of course. If/else statements are much easier to read when nested than something like (c1)?(c2)?(c3)?(c4)?:1:2:3:4. And having huge expressions as function arguments is not fun.
Also keep in mind that nested ternary expressions make refactoring the code - or debugging by placing a bunch of handy printfs() at a condition - a lot harder.