How to get a list of sub-folders and their files, ordered by folder-names

Can I use dir command-line to get a list of sub-folders and their files, ordered by folder-names, and not just file-names ?

using

dir /s/b/o:gn > f.txt

I first get all sub-folders and only then all sub files, e.g.:

 d:\root0\root1\folderA
 d:\root0\root1\folderB
 d:\root0\root1\file00.txt
 d:\root0\root1\file01.txt
 d:\root0\root1\folderA\fileA00.txt
 d:\root0\root1\folderA\fileA01.txt
 d:\root0\root1\folderB\fileB00.txt
 d:\root0\root1\folderB\fileB01.txt

But I want to get -

d:\root0\root1\file00.txt
d:\root0\root1\file01.txt
d:\root0\root1\folderA
d:\root0\root1\folderA\fileA00.txt
d:\root0\root1\folderA\fileA01.txt
d:\root0\root1\folderB
d:\root0\root1\folderB\fileB00.txt
d:\root0\root1\folderB\fileB01.txt

["file00.txt" and "file01.txt" can also be at the end of the list]

Thanks,

Atara

Solution 1:

How about using sort?

dir /b /s | sort

Here's an example I tested with:

dir /s /b /o:gn

d:\root0
d:\root0\root1
d:\root0\root1\folderA
d:\root0\root1\folderB
d:\root0\root1\file00.txt
d:\root0\root1\file01.txt
d:\root0\root1\folderA\fileA00.txt
d:\root0\root1\folderA\fileA01.txt
d:\root0\root1\folderB\fileB00.txt
d:\root0\root1\folderB\fileB01.txt

dir /s /b | sort

d:\root0
d:\root0\root1
d:\root0\root1\file00.txt
d:\root0\root1\file01.txt
d:\root0\root1\folderA
d:\root0\root1\folderA\fileA00.txt
d:\root0\root1\folderA\fileA01.txt
d:\root0\root1\folderB
d:\root0\root1\folderB\fileB00.txt
d:\root0\root1\folderB\fileB01.txt

To just get directories, use the /A:D parameter:

dir /a:d /s /b | sort

Solution 2:

Hej man, why are you using this ?

dir /s/b/o:gn > f.txt (wrong one)

Don't you know what is that 'g' in '/o' ??

Check this out: http://www.computerhope.com/dirhlp.htm or dir /? for dir help

You should be using this instead:

dir /s/b/o:n > f.txt (right one)

Solution 3:

dir /b /a-d /s *.* will fulfill your requirement.