python: get directory two levels up
Ok...I dont know where module x
is, but I know that I need to get the path to the directory two levels up.
So, is there a more elegant way to do:
import os
two_up = os.path.dirname(os.path.dirname(__file__))
Solutions for both Python 2 and 3 are welcome!
You can use pathlib
. Unfortunately this is only available in the stdlib for Python 3.4. If you have an older version you'll have to install a copy from PyPI here. This should be easy to do using pip
.
from pathlib import Path
p = Path(__file__).parents[1]
print(p)
# /absolute/path/to/two/levels/up
This uses the parents
sequence which provides access to the parent directories and chooses the 2nd one up.
Note that p
in this case will be some form of Path
object, with their own methods. If you need the paths as string then you can call str
on them.
Very easy:
Here is what you want:
import os.path as path
two_up = path.abspath(path.join(__file__ ,"../.."))