javascript switch(true)

It works for me:

var a = 0, b = true;
    
switch(true) {
    case a:
        console.log('a');
        break;
    case b:
        console.log('b');
        break;
}

However, the case labels must be equal to true, not jut implicitly true.
Also, only the first case that evaluates to true will execute.

SOLVED

Based on SLaks answer i modify the code as below

    if(j.choice1){ var choice1=true;} else { var choice1=false;}
    if(j.choice2){ var choice2=true;} else { var choice2=false;}

    switch(true)
    {
        case choice1:
            alert("choice1");
        break;
        case choice2:
            alert("choice2");
        break;
        default:
            alert("default");
        break;
    }

For all asking why switch and not if.

Switch will execute only 1 statement, but if can execute more than 1 if any mistake come form response (for example if set choice1 and choice 2 the if will alert both but switch will alert only choice1).

The response expecting as choice has to do with credit card charge to bank so i want to ensure that only 1 action will exetute

Thank to all

You need to read up on the switch statement. You should not be switching on a constant value.

It appears that you need to use if statements, as you don't really want to be switching on your j value:

success: function (j) {     
    if (j.choice1)
    {
        alert("choice1");
        break;
    }

    if (j.choice2)
    {
        alert("choice2");
        break;
    }

    alert("default");
  }
}