Detect numbers or letters with jQuery/JavaScript?
Solution 1:
If you want to check a range of letters you can use greater than and less than:
if (event.keyCode >= 48 && event.keyCode <= 57)
alert("input was 0-9");
if (event.keyCode >= 65 && event.keyCode <= 90)
alert("input was a-z");
For a more dynamic check, use a regular expression:
var inp = String.fromCharCode(event.keyCode);
if (/[a-zA-Z0-9-_ ]/.test(inp))
alert("input was a letter, number, hyphen, underscore or space");
See the MDC documentation for the keyCode
property, which explains the difference between that and the which
property and which events they apply to.
Solution 2:
Use event.key
and modern JS!
No number codes anymore. You can check key
directly.
const key = event.key.toLowerCase();
if (key.length !== 1) {
return;
}
const isLetter = (key >= "a" && key <= "z");
const isNumber = (key >= "0" && key <= "9");
if (isLetter || isNumber) {
// Do something
}
You could also use a simple regex. ^$
ensures 1 char, i
ignores case
/^[a-z0-9]$/i.test(event.key)
or individually:
const isLetter = /^[a-z]$/i.test(event.key)
const isNumber = /^[0-9]$/i.test(event.key)
Solution 3:
First, if you're doing this, make sure it's in the keypress
event, which is the only event for which you can reliably obtain information about the character the user has typed. Then I'd use the approach Andy E suggested:
document.onkeypress = function(evt) {
evt = evt || window.event;
var charCode = evt.which || evt.keyCode;
var charStr = String.fromCharCode(charCode);
if (/[a-z0-9]/i.test(charStr)) {
alert("Letter or number typed");
}
};
If you want to check for backspace, I'd use the keydown
event instead and check for a keyCode
of 8 because several browsers (including Chrome) do not fire a keypress
event for the backspace key.
Solution 4:
if(event.keyCode >= 48 && event.keyCode <= 90) {
//the key pressed was alphanumeric
}
Solution 5:
As @Gibolt said, you should Use event.key
Because charCode, keyCode and Which are being deprecated.