Why is $i^i$ real? [duplicate]
Using Euler's formula:
$$ i = e^{i\pi / 2} $$
So:
$$ i^i = (e^{i\pi / 2})^i = e^{i^2\pi/2} = e^{-\pi/2} = 0.207... $$
Why is $i^i$ real? [duplicate]
Using Euler's formula:
$$ i = e^{i\pi / 2} $$
So:
$$ i^i = (e^{i\pi / 2})^i = e^{i^2\pi/2} = e^{-\pi/2} = 0.207... $$