Detect consecutive dates ranges using SQL
I want to fill the calendar object which requires start and end date information. I have one column which contains a sequence of dates. Some of the dates are consecutive (have one day difference) and some are not.
InfoDate
2013-12-04 consecutive date [StartDate]
2013-12-05 consecutive date
2013-12-06 consecutive date [EndDate]
2013-12-09 [startDate]
2013-12-10 [EndDate]
2014-01-01 [startDate]
2014-01-02
2014-01-03 [EndDate]
2014-01-06 [startDate]
2014-01-07 [EndDate]
2014-01-29 [startDate]
2014-01-30
2014-01-31 [EndDate]
2014-02-03 [startDate]
2014-02-04 [EndDate]
I want to pick each consecutive dates range’s start and end date (the first one and the last one in the block).
StartDate EndDate
2013-12-04 2013-12-06
2013-12-09 2013-12-10
2014-01-01 2014-01-03
2014-01-06 2014-01-07
2014-01-29 2014-01-31
2014-02-03 2014-02-04
I want to solve the problem using SQL only.
No joins or recursive CTEs needed. The standard gaps-and-island solution is to group by (value minus row_number), since that is invariant within a consecutive sequence. The start and end dates are just the MIN() and MAX() of the group.
WITH t AS (
SELECT InfoDate d,ROW_NUMBER() OVER(ORDER BY InfoDate) i
FROM @d
GROUP BY InfoDate
)
SELECT MIN(d),MAX(d)
FROM t
GROUP BY DATEDIFF(day,i,d)
Here you go..
;WITH CTEDATES
AS
(
SELECT ROW_NUMBER() OVER (ORDER BY Infodate asc ) AS ROWNUMBER,infodate FROM YourTableName
),
CTEDATES1
AS
(
SELECT ROWNUMBER, infodate, 1 as groupid FROM CTEDATES WHERE ROWNUMBER=1
UNION ALL
SELECT a.ROWNUMBER, a.infodate,case datediff(d, b.infodate,a.infodate) when 1 then b.groupid else b.groupid+1 end as gap FROM CTEDATES A INNER JOIN CTEDATES1 B ON A.ROWNUMBER-1 = B.ROWNUMBER
)
select min(mydate) as startdate, max(infodate) as enddate from CTEDATES1 group by groupid
please don't forget to mark it as answer, if this answers your question.