Why do I need to explicitly push a new branch?
Solution 1:
The actual reason is that, in a new repo (git init), there is no branch (no master
, no branch at all, zero branches)
So when you are pushing for the first time to an empty upstream repo (generally a bare one), that upstream repo has no branch of the same name.
And:
- the default push policy was '
matching
' (push all the branches of the same name, creating them if they don't exist), - the default push policy is now '
simple
' (push only the current branch, and only if it has a similarly named remote tracking branch on upstream, since git 1.7.11)
In both cases, since the upstream empty repo has no branch:
- there is no matching named branch yet
- there is no upstream branch at all (with or without the same name! Tracking or not)
That means your local first push has no idea:
- where to push
- what to push (since it cannot find any upstream branch being either recorded as a remote tracking branch, and/or having the same name)
So you need at least to do a:
git push origin master
But if you do only that, you:
- will create an upstream
master
branch on the upstream (now non-empty repo): good. - won't record that the local branch '
master
' needs to be pushed to upstream (origin
) 'master
' (upstream branch): bad.
That is why it is recommended, for the first push, to do a:
git push -u origin master
That will record origin/master
as a remote tracking branch, and will enable the next push to automatically push master
to origin/master
.
git checkout master
git push
And that will work too with push policies 'current
' or 'upstream
'.
In each case, after the initial git push -u origin master
, a simple git push will be enough to continue pushing master to the right upstream branch.
Solution 2:
You don't, see below
I find this 'feature' rather annoying since I'm not trying to launch rockets to the moon, just push my damn branch. You probably do too or else you wouldn't be here!
Here is the fix: if you want it to implicitly push for the current branch regardless of if that branch exists on origin just issue this command once and you will never have to again anywhere:
git config --global push.default current
So if you make branches like this:
git checkout -b my-new-branch
and then make some commits and then do a
git push -u
to get them out to origin (being on that branch) and it will create said branch for you if it doesn't exist.
Note the -u bit makes sure they are linked if you were to pull later on from said branch. If you have no plans to pull the branch later (or are okay with another one liner if you do) -u is not necessary.
Solution 3:
Output of git push
when pushing a new branch
> git checkout -b new_branch
Switched to a new branch 'new_branch'
> git push
fatal: The current branch new_branch has no upstream branch.
To push the current branch and set the remote as upstream, use
git push --set-upstream origin new_branch
A simple git push
assumes that there already exists a remote branch that the current local branch is tracking. If no such remote branch exists, and you want to create it, you must specify that using the -u
(short form of --set-upstream
) flag.
Why this is so? I guess the implementers felt that creating a branch on the remote is such a major action that it should be hard to do it by mistake. git push
is something you do all the time.
"Isn't a branch a new change to be pushed by default?" I would say that "a change" in Git is a commit. A branch is a pointer to a commit. To me it makes more sense to think of a push as something that pushes commits over to the other repositories. Which commits are pushed is determined by what branch you are on and the tracking relationship of that branch to branches on the remote.
You can read more about tracking branches in the Remote Branches chapter of the Pro Git book.