How to access OWL documents using XPath in Java?
Don't query RDF (or OWL) with XPath
There's already an accepted answer, but I wanted to elaborate on @Michael's comment on the question. It's a very bad idea to try to work with RDF as XML (and hence, the RDF serialization of an OWL ontology), and the reason for that is very simple: the same RDF graph can be serialized as lots of different XML documents. In the question, all that's being asked for the is rdfs:label
of an owl:Ontology
element, so how much could go wrong? Well, here are two serializations of the ontology.
The first is fairly human readable, and was generated by the OWL API when I saved the ontology using the Protégé ontology editor. The query in the accepted answer would work on this, I think.
<rdf:RDF xmlns="http://www.example.com/labelledOnt#"
xml:base="http://www.example.com/labelledOnt"
xmlns:rdfs="http://www.w3.org/2000/01/rdf-schema#"
xmlns:owl="http://www.w3.org/2002/07/owl#"
xmlns:xsd="http://www.w3.org/2001/XMLSchema#"
xmlns:rdf="http://www.w3.org/1999/02/22-rdf-syntax-ns#">
<owl:Ontology rdf:about="http://www.example.com/labelledOnt">
<rdfs:label>Here is a label on the Ontology.</rdfs:label>
</owl:Ontology>
</rdf:RDF>
Here is the same RDF graph using fewer of the fancy features available in the RDF/XML encoding. This is the same RDF graph, and thus the same OWL ontology. However, there is no owl:Ontology
XML element here, and the XPath query will fail.
<rdf:RDF
xmlns:rdf="http://www.w3.org/1999/02/22-rdf-syntax-ns#"
xmlns:owl="http://www.w3.org/2002/07/owl#"
xmlns:xsd="http://www.w3.org/2001/XMLSchema#"
xmlns="http://www.example.com/labelledOnt#"
xmlns:rdfs="http://www.w3.org/2000/01/rdf-schema#" >
<rdf:Description rdf:about="http://www.example.com/labelledOnt">
<rdf:type rdf:resource="http://www.w3.org/2002/07/owl#Ontology"/>
<rdfs:label>Here is a label on the Ontology.</rdfs:label>
</rdf:Description>
</rdf:RDF>
You cannot reliably query an RDF graph in RDF/XML serialization by using typical XML-processing techniques.
Query RDF with SPARQL
Well, if we cannot query reliably query RDF with XPath, what are we supposed to use? The standard query language for RDF is SPARQL. RDF is a graph-based representation, and SPARQL queries include graph patterns that can match a graph.
In this case, the pattern that we want to match in a graph consists of two triples. A triple is a 3-tuple of the form [subject,predicate,object]
. Both triples have the same subject.
- The first triple says that the subject is of type
owl:Ontology
. The relationship “is of type” isrdf:type
, so the first triple is[?something,rdf:type,owl:Ontology]
. - The second triple says that subject (now known to be an ontology) has an
rdfs:label
, and that's the value that we're interested in. The corresponding triple is[?something,rdfs:label,?label]
.
In SPARQL, after defining the necessary prefixes, we can write the following query.
PREFIX owl: <http://www.w3.org/2002/07/owl#>
PREFIX rdfs: <http://www.w3.org/2000/01/rdf-schema#>
SELECT ?label WHERE {
?ontology a owl:Ontology ;
rdfs:label ?label .
}
(Note that because rdf:type
is so common, SPARQL includes a
as an abbreviation for it. The notation s p1 o1; p2 o2 .
is just shorthand for the two-triple pattern s p1 o1 . s p2 o2 .
.)
You can run SPARQL queries against your model in Jena either programmatically, or using the command line tools. If you do it programmatically, it is fairly easy to get the results out. To confirm that this query gets the value we're interested in, we can use Jena's command line for arq
to test it out.
$ arq --data labelledOnt.owl --query getLabel.sparql
--------------------------------------
| label |
======================================
| "Here is a label on the Ontology." |
--------------------------------------
as xpath does not know the namespaces you are using. try using:
"/*[local-name()='RDF']/*[local-name()='Ontology']/*[local-name()='label']/text()"
local name will ignore the namespaces and will work (for the first instance of this that it finds)
You would be able to use namespaces in query if you implement javax.xml.namespace.NamespaceContext
for yourself. Please have a look at this answer https://stackoverflow.com/a/5466030/1443529, this explains how to get it done.