How to sort text by last column?

This command

udisksctl status

with Ubuntu 20.04.3 gives:

MODEL                     REVISION  SERIAL               DEVICE
--------------------------------------------------------------------------
SanDisk Extreme           0001      AA010302161107080264 sdb     
ATAPI   DVD A  DH17A3L    8H3D      ATAPI_DVD_A_DH17A3L  sr0     
KINGSTON SA400S27230G     S3Z40107  50016B7683B02C0B     sda     
Optiarc DVD RW AD-7580A   1.04      Optiarc_DVD_RW_AD-7580A sr0     
HL-DT-STDVD-RAM GH22NS30  2.00      HL-DT-STDVD-RAM_GH22NS30 sr0 
Floppy Drive                                             fd0     
Generic Flash Disk        8.07      162194AF             sdc     

The target is to sort by the last 3 characters in each line (after the header), giving:

Floppy Drive                                             fd0     
KINGSTON SA400S27230G     S3Z40107  50016B7683B02C0B     sda     
SanDisk Extreme           0001      AA010302161107080264 sdb     
Generic Flash Disk        8.07      162194AF             sdc     
Optiarc DVD RW AD-7580A   1.04      Optiarc_DVD_RW_AD-7580A sr0     
ATAPI   DVD A  DH17A3L    8H3D      ATAPI_DVD_A_DH17A3L  sr0     
HL-DT-STDVD-RAM GH22NS30  2.00      HL-DT-STDVD-RAM_GH22NS30 sr0 

I got partial success with

udisksctl status | tail -n+3 | rev | sort -b -k1.1 | rev | grep 'sd\|hd\|fd\|sr\|st'



udisksctl status | tail -n+3 

from bottom (tail) to line 3 thus cut out 2 line header:

MODEL                     REVISION  SERIAL               DEVICE
--------------------------------------------------------------------------

udisksctl status | tail -n+3 | rev |

Reverse, bring last characters in a line to the front of the line.

udisksctl status | tail -n+3 | rev | sort -b -k1.1 

sort -b = ignore leading blanks
-k1.1 = sort via key first letter after ignored blanks

udisksctl status | tail -n+3 | rev | sort -b -k1.1 | rev 

undo reverse

udisksctl status | tail -n+3 | rev | sort -b -k1.1 | rev | grep 'sd\|hd\|fd\|sr\|st'

Highlight with grep:

• sd  Scsi Device
• hd  Hard Disk Drive
• fd  Floppy Drive
• sr  Scsi ROM, cdrom, dvd
• st  Scsi Tape Drive
• ...

For simplicity focus on last 3 letters. The problem is how to do a sort to get:

fd0     
sda     
sdb     
sdc     
sr0     
sr0     
sr0     

Because the problem as shown above is last 1 letter is sorted not last 3 letters:

fd0     
sr0     
sr0     
sr0     
sda     
sdb     
sdc     

How can I sort by the last 3 characters in a line?  (The lines have different lengths.)

Try this:

udisksctl status | awk '{ print $NF,$0 }' | sort -k1,1 -n | cut -f2- -d' '

That takes care also longer strings like nvme0n1 as sorting is done by last column, not a number of characters.

I don't have udiskctl, but tested by copying your list to a file sortof, adding NVM drive to verify and catting the file:

pg@TREX:~/test$ cat sortof | awk '{ print $NF,$0 }' | sort -k1,1 -n | cut -f2- -d' '
HL-DT-STDVD-RAM GH22NS30 2.00 HL-DT-STDVD-RAM_GH22NS30 sr0 Floppy Drive fd0
KINGSTON SA400S27230G S3Z40107 50016B7683B02C0B nvme1p
KINGSTON SA400S27230G S3Z40107 50016B7683B02C0B sda
SanDisk Extreme 0001 AA010302161107080264 sdb
Generic Flash Disk 8.07 162194AF sdc
ATAPI DVD A DH17A3L 8H3D ATAPI_DVD_A_DH17A3L sr0
Optiarc DVD RW AD-7580A 1.04 Optiarc_DVD_RW_AD-7580A sr0

... so it should work also when you pipe the udiskctl output.