Get all fields (even private and inherited) from class

obj = obj.getClass().getSuperclass().cast(obj);

This line does not do what you expect it to do. Casting an Object does not actually change it, it just tells the compiler to treat it as something else.

E.g. you can cast a List to a Collection, but it will still remain a List.

However, looping up through the super classes to access fields works fine without casting:

Class<?> current = yourClass;
while(current.getSuperclass()!=null){ // we don't want to process Object.class
    // do something with current's fields
    current = current.getSuperclass();
}

BTW, if you have access to the Spring Framework, there is a handy method for looping through the fields of a class and all super classes:
ReflectionUtils.doWithFields(baseClass, FieldCallback)
(also see this previous answer of mine: Access to private inherited fields via reflection in Java)

getDeclaredFields() gives you all fields on that Class, including private ones.

getFields() gives you all public fields on that Class AND it's superclasses.

If you want private / protected methods of Super Classes, you will have to repeatedly call getSuperclass() and then call getDeclaredFields() on the Super Class object.

Nothing here isn't clearly explained in the javadocs

Here is the method I use to get all the fields of an object

private <T> List<Field> getFields(T t) {
        List<Field> fields = new ArrayList<>();
        Class clazz = t.getClass();
        while (clazz != Object.class) {
            fields.addAll(Arrays.asList(clazz.getDeclaredFields()));
            clazz = clazz.getSuperclass();
        }
        return fields;
    }