Checking strings against each other (Anagrams)

The assignment is to write a program that accepts two groups of words from the user and then prints a "True" statement if the two are anagrams (or at least if all the letters of one are present in the other) and a "False" statement if not.

Being very new to programming as a whole, I don't know how to move beyond just indexing a string and comparing all of the pieces of one to another. I stress that I am a beginner; I've read many of the other posts tagged with Python and Anagram, and they are uniformly above my head and reference things I have not been taught. So the simpler the better. Here is my non-working code so far:

s1 = input("Please enter a word:")
s2 = input("Please enter another word:")

for i in range(0, len(s1), 1):
    if i in range (0, len(s2), 1):
        print("The letters in your first word are present in your second word.")

Why not just sort the strings?

>>> sorted('anagram')
['a', 'a', 'a', 'g', 'm', 'n', 'r']
>>> sorted('nagaram')
['a', 'a', 'a', 'g', 'm', 'n', 'r']
>>> sorted('anagram') == sorted('nagaram')
True

You can use the magic Counter from collections library. From documentation:

It is an unordered collection where elements are stored as dictionary keys and their counts are stored as dictionary values

So, you can initialize a Counter object with a string (a iterable) and compare with another Counter from a string

from collections import Counter

def is_anagram(str1, str2):
   return Counter(str1) == Counter(str2)

You need to think through your conditional logic a bit more. The loop is on the right track, but if there is a letter in s1 that is NOT in s2, you should break out of this loop and print the "False" statement. Consider using a variable like all_s1_in_s2 = True and then setting that to false if you find a letter that doesn't match.

Some other tips:

• for l in s1 will loop through string s1 giving you access to each letter in sequence as l - you don't need range or len at all

• The if .. in statement can help test whether a letter exists in a string, e.g. if letter in mystring: is a valid statement and this could help you a lot, again not needing range or len

• You should avoid using numbers in variable names where possible - better would be word_one and word_two, as an example

To check if two strings are anagrams of each other using dictionaries: Note : Even Number, special characters can be used as an input

def anagram(s):
    string_list = []
    for ch in s.lower():
        string_list.append(ch)

    string_dict = {}
    for ch in string_list:
        if ch not in string_dict:
            string_dict[ch] = 1
        else:
            string_dict[ch] = string_dict[ch] + 1

    return string_dict



s1 = "master"
s2 = "stream"

a = anagram(s1)
b = anagram(s2)

if a == b:
    print "Anagram"
else:
    print "Not Anagram"