Get unique values from ArrayList in Java

You should use a Set. A Set is a Collection that contains no duplicates.

If you have a List that contains duplicates, you can get the unique entries like this:

List<String> gasList = // create list with duplicates...
Set<String> uniqueGas = new HashSet<String>(gasList);
System.out.println("Unique gas count: " + uniqueGas.size());

NOTE: This HashSet constructor identifies duplicates by invoking the elements' equals() methods.

You can use Java 8 Stream API.

Method distinct is an intermediate operation that filters the stream and allows only distinct values (by default using the Object::equals method) to pass to the next operation.
I wrote an example below for your case,

// Create the list with duplicates.
List<String> listAll = Arrays.asList("CO2", "CH4", "SO2", "CO2", "CH4", "SO2", "CO2", "CH4", "SO2");

// Create a list with the distinct elements using stream.
List<String> listDistinct = listAll.stream().distinct().collect(Collectors.toList());

// Display them to terminal using stream::collect with a build in Collector.
String collectAll = listAll.stream().collect(Collectors.joining(", "));
System.out.println(collectAll); //=> CO2, CH4, SO2, CO2, CH4 etc..
String collectDistinct = listDistinct.stream().collect(Collectors.joining(", "));
System.out.println(collectDistinct); //=> CO2, CH4, SO2

I hope I understand your question correctly: assuming that the values are of type String, the most efficient way is probably to convert to a HashSet and iterate over it:

ArrayList<String> values = ... //Your values
HashSet<String> uniqueValues = new HashSet<>(values);
for (String value : uniqueValues) {
   ... //Do something
}