Newbetuts

equivalence in Uniform convergence and space of bounded functions. Requirement of functions $f_n$ and $f$ are bounded function.

Proof that extreme estimators are consistent

Riemann Integrable and Uniform Convergence

Does absolute convergence of a sum imply uniform convergence?

Weak convergence in probability implies uniform convergence in distribution functions

Convergence in law implies uniform convergence of cdf's

Intuitive explanation of proof of Abel's limit theorem

Does a continuous point-wise limit imply uniform convergence?

Uniform convergence of functions and intervals

$\lVert f_n \rVert_{\text{sup}} \to 0$ and $\frac{f_n(x)}{a_n} \to 0$ implies $\frac{\lVert f_n \rVert_{\text{sup}}}{a_n} \to 0 $?

Prove $x^n$ is not uniformly convergent

Uniformly equicontinuous sequence of functions that does not converge uniformly

If $f(x+1/n)$ converges to a continuous function $f(x)$ uniformly on $\mathbb{R}$, is $f(x)$ necessarily uniformly continuous?

Pointwise but not Uniformly Convergent

New posts in uniform-convergence

Relation between uniform continuity and uniform convergence

Sup Norm and Uniform Convergence

Converge uniformly on open interval implies on closed interval

Uniform continuous maps that converge uniformly to a function f. What can we say about f?

If $\int_0^1 e^{- \frac{nx}{1-x}} f(x) \; dx =0$ for $n \geq 0$, then $f=0$ on $[0,1]$

Uniform convergence on two separate intervals

equivalence in Uniform convergence and space of bounded functions. Requirement of functions $f_n$ and $f$ are bounded function.

Proof that extreme estimators are consistent

Riemann Integrable and Uniform Convergence

Does absolute convergence of a sum imply uniform convergence?

Weak convergence in probability implies uniform convergence in distribution functions

Convergence in law implies uniform convergence of cdf's

Intuitive explanation of proof of Abel's limit theorem

Does a continuous point-wise limit imply uniform convergence?

Uniform convergence of functions and intervals

$\lVert f_n \rVert_{\text{sup}} \to 0$ and $\frac{f_n(x)}{a_n} \to 0$ implies $\frac{\lVert f_n \rVert_{\text{sup}}}{a_n} \to 0 $?

Prove $x^n$ is not uniformly convergent

Uniformly equicontinuous sequence of functions that does not converge uniformly

If $f(x+1/n)$ converges to a continuous function $f(x)$ uniformly on $\mathbb{R}$, is $f(x)$ necessarily uniformly continuous?

Pointwise but not Uniformly Convergent