can someone please explain me @MapsId in hibernate?
Solution 1:
Here is a nice explanation from Object DB.
Designates a ManyToOne or OneToOne relationship attribute that provides the mapping for an EmbeddedId primary key, an attribute within an EmbeddedId primary key, or a simple primary key of the parent entity. The value element specifies the attribute within a composite key to which the relationship attribute corresponds. If the entity's primary key is of the same Java type as the primary key of the entity referenced by the relationship, the value attribute is not specified.
// parent entity has simple primary key
@Entity
public class Employee {
@Id long empId;
String name;
...
}
// dependent entity uses EmbeddedId for composite key
@Embeddable
public class DependentId {
String name;
long empid; // corresponds to primary key type of Employee
}
@Entity
public class Dependent {
@EmbeddedId DependentId id;
...
@MapsId("empid") // maps the empid attribute of embedded id
@ManyToOne Employee emp;
}
Read the API Docs here.
Solution 2:
I found this note also useful: @MapsId
in hibernate annotation maps a column with another table's column.
It can be used also to share the same primary key between 2 tables.
Example:
@Entity
@Table(name = "TRANSACTION_CANCEL")
public class CancelledTransaction {
@Id
private Long id; // the value in this pk will be the same as the
// transaction line from transaction table to which
// this cancelled transaction is related
@OneToOne(fetch = FetchType.LAZY)
@JoinColumn(name = "ID_TRANSACTION", nullable = false)
@MapsId
private Transaction transaction;
....
}
@Entity
@Table(name = "TRANSACTION")
@SequenceGenerator(name = "SQ_TRAN_ID", sequenceName = "SQ_TRAN_ID")
public class Transaction {
@Id
@GeneratedValue(generator = "SQ_TRAN_ID", strategy = GenerationType.SEQUENCE)
@Column(name = "ID_TRANSACTION", nullable = false)
private Long id;
...
}
Solution 3:
IMHO, the best way to think about @MapsId
is when you need to map a composite key in a n:m entity.
For instance, a customer can have one or more consultant and a consultant can have one or more customer:
And your entites would be something like this (pseudo Java code):
@Entity
public class Customer {
@Id
private Integer id;
private String name;
}
@Entity
public class Consultant {
@Id
private Integer id;
private String name;
@OneToMany
private List<CustomerByConsultant> customerByConsultants = new ArrayList<>();
public void add(CustomerByConsultant cbc) {
cbc.setConsultant(this);
this.customerByConsultant.add(cbc);
}
}
@Embeddable
public class ConsultantByConsultantPk implements Serializable {
private Integer customerId;
private Integer consultantId;
}
@Entity
public class ConsultantByConsultant {
@EmbeddedId
private ConsultantByConsultantPk id = new ConsultantByConsultantPk();
@MapsId("customerId")
@JoinColumn(insertable = false, updatable = false)
private Customer customer;
@MapsId("consultantId")
@JoinColumn(insertable = false, updatable = false)
private Consultant consultant;
}
Mapping this way, JPA automagically inserts Customer
and Consultant
ids in the EmbeddableId
whenever you save a consultant. So you don't need to manually create the ConsultantByConsultantPk
.