I am not completely sure, and I cannot provide a publicly available reference, but I read in some lecture notes from our university that this decomposition can be generalized to $\mathbb{R}^n$. Let $\lambda$ be the Lebesgue measure on $\mathbb{R}^n$ and $\mu$ the measure under consideration. Then,

$$ \mu = \mu_a + \mu_s + \mu_d $$

where $\mu_d$ is discrete (i.e., supported on a countable set, with positive measure for every atom), $\mu_a$ is absolutely continuous w.r.t. $\lambda$ (i.e., it possesses a density), and $\mu_s$ is singularly continuous, i.e., it is supported on a Lebesgue null-set, and the atoms of this set have zero measure.

An example for $\mu_s$ in $\mathbb{R}^2$ would be a measure which is supported on a one-dimensional submanifold of $\mathbb{R}^2$, e.g., the uniform distribution on the unit circle.


In the case of Borel measures on the real line, the continuous singular part $\nu_\mathrm{sing}$ can be characterized as follows: First let $$ F(x) = \nu_\mathrm{sing}((-\infty,x]). $$ (In the special case of probability measures, this is the cumulative probability distribution function.) Then $F$ is a continuous function, but $\nu_\mathrm{sing}$ and Lebesgue measure are mutually singular.

The Cantor function in the role of $F$ is an example. The Cantor distribution is a probability distribution no part of which has a density with respect to Lebesgue measure. But its cumulative distribution function is nonetheless continuous. I.e. there is no function $f$ such that for every Borel set $A$, $$ \nu(A) = \int_A f(x)\;dx + \nu_\mathrm{singular}(A) $$ for some other measure $\nu_\mathrm{singular}$ (except the trivial function $f=0)$.


A singular (say, probability) measures $\mu$ with respect to the Lebesgue measure $\lambda$ on $\mathbb R^d$ satisfies by definition: there exists a Borel set $S$ such that $\mu(S)=1$ and $\lambda(S)=0$. To obtain a continuous singular measure, that is satisfying $\mu(\{x\})=0$ for any $x\in\mathbb R^d$, the idea is to find a measure supported on a set $S$ having positive dimension but strictly less than $d$. When $d=1$, you can use sets of fractional dimension, like the cantor set, but in higher dimension you can find more easy examples, e.g. taking for $\mu$ a measure on the unit circle (resp. sphere) in $\mathbb R^2$ (resp. $\mathbb R^d$).