How to remove all namespaces from XML with C#?
Solution 1:
Well, here is the final answer. I have used great Jimmy idea (which unfortunately is not complete itself) and complete recursion function to work properly.
Based on interface:
string RemoveAllNamespaces(string xmlDocument);
I represent here final clean and universal C# solution for removing XML namespaces:
//Implemented based on interface, not part of algorithm
public static string RemoveAllNamespaces(string xmlDocument)
{
XElement xmlDocumentWithoutNs = RemoveAllNamespaces(XElement.Parse(xmlDocument));
return xmlDocumentWithoutNs.ToString();
}
//Core recursion function
private static XElement RemoveAllNamespaces(XElement xmlDocument)
{
if (!xmlDocument.HasElements)
{
XElement xElement = new XElement(xmlDocument.Name.LocalName);
xElement.Value = xmlDocument.Value;
foreach (XAttribute attribute in xmlDocument.Attributes())
xElement.Add(attribute);
return xElement;
}
return new XElement(xmlDocument.Name.LocalName, xmlDocument.Elements().Select(el => RemoveAllNamespaces(el)));
}
It's working 100%, but I have not tested it much so it may not cover some special cases... But it is good base to start.
Solution 2:
The tagged most useful answer has two flaws:
- It ignores attributes
- It doesn't work with "mixed mode" elements
Here is my take on this:
public static XElement RemoveAllNamespaces(XElement e)
{
return new XElement(e.Name.LocalName,
(from n in e.Nodes()
select ((n is XElement) ? RemoveAllNamespaces(n as XElement) : n)),
(e.HasAttributes) ?
(from a in e.Attributes()
where (!a.IsNamespaceDeclaration)
select new XAttribute(a.Name.LocalName, a.Value)) : null);
}
Sample code here.
Solution 3:
That will do the trick :-)
foreach (XElement XE in Xml.DescendantsAndSelf())
{
// Stripping the namespace by setting the name of the element to it's localname only
XE.Name = XE.Name.LocalName;
// replacing all attributes with attributes that are not namespaces and their names are set to only the localname
XE.ReplaceAttributes((from xattrib in XE.Attributes().Where(xa => !xa.IsNamespaceDeclaration) select new XAttribute(xattrib.Name.LocalName, xattrib.Value)));
}
Solution 4:
the obligatory answer using LINQ:
static XElement stripNS(XElement root) {
return new XElement(
root.Name.LocalName,
root.HasElements ?
root.Elements().Select(el => stripNS(el)) :
(object)root.Value
);
}
static void Main() {
var xml = XElement.Parse(@"<?xml version=""1.0"" encoding=""utf-16""?>
<ArrayOfInserts xmlns:xsi=""http://www.w3.org/2001/XMLSchema-instance"" xmlns:xsd=""http://www.w3.org/2001/XMLSchema"">
<insert>
<offer xmlns=""http://schema.peters.com/doc_353/1/Types"">0174587</offer>
<type2 xmlns=""http://schema.peters.com/doc_353/1/Types"">014717</type2>
<supplier xmlns=""http://schema.peters.com/doc_353/1/Types"">019172</supplier>
<id_frame xmlns=""http://schema.peters.com/doc_353/1/Types"" />
<type3 xmlns=""http://schema.peters.com/doc_353/1/Types"">
<type2 />
<main>false</main>
</type3>
<status xmlns=""http://schema.peters.com/doc_353/1/Types"">Some state</status>
</insert>
</ArrayOfInserts>");
Console.WriteLine(stripNS(xml));
}
Solution 5:
Pick it up again, in C# - added line for copying the attributes:
static XElement stripNS(XElement root)
{
XElement res = new XElement(
root.Name.LocalName,
root.HasElements ?
root.Elements().Select(el => stripNS(el)) :
(object)root.Value
);
res.ReplaceAttributes(
root.Attributes().Where(attr => (!attr.IsNamespaceDeclaration)));
return res;
}