How to get a slice from "arguments"
All you know that arguments
is a special object that holds all the arguments passed to the function.
And as long as it is not an array - you cannot use something like arguments.slice(1)
.
So the question - how to slice everything but first element from arguments
?
UPD:
seems like there is no way without converting it to an array with
var args = Array.prototype.slice.call(arguments);
If someone posts another solution it would be great, if not - I'll check the first one with the line above as an answer.
Solution 1:
Q. How to slice everything but first element from arguments
?
The following will return an array containing all arguments except the first:
var slicedArgs = Array.prototype.slice.call(arguments, 1);
You don't have to convert arguments
to an array first, do it all in one step.
Solution 2:
Meddling with array functions is not actually necessary.
Using rest parameter syntax ...rest
is cleaner and more convenient.
Example
function argumentTest(first, ...rest) {
console.log("First arg:" + first);
// loop through the rest of the parameters
for (let arg of rest) {
console.log("- " + arg);
}
}
// call your function with any number of arguments
argumentTest("first arg", "#2", "more arguments", "this is not an argument but a contradiction");
...Rest
- See the example Fiddle
- See MDN Documentation page