Why does assigning to my global variables not work in Python?

Solution 1:

Global variables are special. If you try to assign to a variable a = value inside of a function, it creates a new local variable inside the function, even if there is a global variable with the same name. To instead access the global variable, add a global statement inside the function:

a = 7
def setA(value):
    global a   # declare a to be a global
    a = value  # this sets the global value of a

See also Naming and binding for a detailed explanation of Python's naming and binding rules.

Solution 2:

The trick to understanding this is that when you assign to a variable, using =, you also declare it as a local variable. So instead of changing the value of the global variable a, setA(value) actually sets a local variable (which happens to be called a) to the value passed in.

This becomes more obvious if you try to print the value of a at the start of setA(value) like so:

def setA(value):
    print "Before assignment, a is %d" % (a)
    a = value
    print "Inside setA, a is now %d" % (a)

If you try to run this Python will give you a helpful error:

Traceback (most recent call last):
  File "scopeTest.py", line 14, in 
    setA(42)
  File "scopeTest.py", line 7, in setA
    print "Before assignment, a is %d" % (a)
UnboundLocalError: local variable 'a' referenced before assignment

This tells us that Python has decided that the setA(value) function has a local variable called a, which is what you alter when you assign to it in the function. If you don't assign to a in the function (as with printA()) then Python uses the global variable A.

To mark a variable as global you need to use the global keyword in Python, in the scope that you want to use the global variable. In this case that is within the setA(value) function. So the script becomes:

a = 7

def printA():
    print "Value of a is %d" % (a)

def setA(value):
    global a
    a = value
    print "Inside setA, a is now %d" %(a)


print "Before setA"
printA()
setA(42)
print "After setA"
printA()

This one line addition tells Python that when you use the variable a in the setA(value) function that you are talking about the global variable, not a local variable.

Solution 3:

inside the function,a is treated as a local variable,you need to define

global a

inside the function before using it inside the method, even though you had defined it outside the method.