How to skip saturday and sunday in a cron expression?
Begin the line with 0 0 * * 1,2,3,4,5 <user> <command>. The first fields are minutes and hours. In this case the command will run at midnight. The stars mean: for every day of the month, and for every month. The 1 to 5 specify the days. monday to friday. 6=saturday 0=sunday.
Try this:
# run every two hours at the top of the hour Monday through Friday
0 */2 * * mon-fri <command>