How can I save colors in array.xml and get its back to Color[] array
Define your color resources, then add them to an array for access.
<?xml version="1.0" encoding="utf-8"?>
<resources>
<color name="bright_pink">#FF007F</color>
<color name="red">#FF0000</color>
<color name="orange">#FF7F00</color>
<color name="yellow">#FFFF00</color>
<color name="chartreuse">#7FFF00</color>
<color name="green">#00FF00</color>
<color name="spring_green">#00FF7F</color>
<color name="cyan">#00FFFF</color>
<color name="azure">#007FFF</color>
<color name="blue">#0000FF</color>
<color name="violet">#7F00FF</color>
<color name="magenta">#FF00FF</color>
<array name="rainbow">
<item>@color/bright_pink</item>
<item>@color/red</item>
<item>@color/orange</item>
<item>@color/yellow</item>
<item>@color/chartreuse</item>
<item>@color/green</item>
<item>@color/spring_green</item>
<item>@color/cyan</item>
<item>@color/azure</item>
<item>@color/blue</item>
<item>@color/violet</item>
<item>@color/magenta</item>
</array>
</resources>
Then access them like this:
int[] rainbow = context.getResources().getIntArray(R.array.rainbow);
for (int i = 0; i < tileColumns; i++) {
paint.setColor(rainbow[i]);
// Do something with the paint.
}
If this is in array.xml:
<resources>
<array name="colors">
<item>#ffffff</item>
<item>#000000</item>
</array>
</resources>
This will give you the color values for that array:
TypedArray ta = context.getResources().obtainTypedArray(R.array.colors);
int[] colors = new int[ta.length()];
for (int i = 0; i < ta.length(); i++) {
colors[i] = ta.getColor(i, 0);
}
ta.recycle();
This just expands on the TypedArray example in the docs: http://developer.android.com/guide/topics/resources/more-resources.html#TypedArray
Hope it helps!
colors.xml
<resources>
<string-array name="colors">
<item>#ff0000</item>
<item>#00ff00</item>
<item>#0000ff</item>
</string-array>
</resources>
Code in activity class.
String[] allColors = context.getResources().getStringArray(R.array.colors);
Color.parseColor(allColors[0]) // red
Color.parseColor(allColors[1]) // green
Color.parseColor(allColors[2]) // blue
I can't post a comment, so I must put this in as a new response. I completely agree with Sky Kelsey w.r.t. design choice of using color resource type. However, I found the suggest method to access them did not work. This is the way I implemented the use of an XML array to easily loop through a list of colors and apply the colors to various (Custom painted) views.
First the array in arrays.xml:
<array name="ingr_color_arr">
<item>@color/ingr_red1</item>
<item>@color/ingr_orange1</item>
<item>@color/ingr_yellow1</item>
<item>@color/ingr_green1</item>
<item>@color/ingr_blue1</item>
<item>@color/ingr_violet1</item>
<item>@color/ingr_red2</item>
<item>@color/ingr_orange2</item>
<item>@color/ingr_yellow2</item>
<item>@color/ingr_green2</item>
<item>@color/ingr_blue2</item>
<item>@color/ingr_violet2</item>
</array>
Then in color.xml:
<color name="ingr_red1">#FFCC0000</color>
<color name="ingr_orange1">#FFED5F21</color>
<color name="ingr_yellow1">#FFFAE300</color>
<color name="ingr_green1">#FF5B9C0A</color>
<color name="ingr_blue1">#FF0A0D9C</color>
<color name="ingr_violet1">#FF990A9C</color>
<color name="ingr_red2">#FFFFCCCC</color>
<color name="ingr_orange2">#FFFFEACC</color>
<color name="ingr_yellow2">#FFFFFECC</color>
<color name="ingr_green2">#FFC7F5C4</color>
<color name="ingr_blue2">#FFC4DAF4</color>
<color name="ingr_violet2">#FFE1C4F4</color>
Then to use it:
TypedArray ta = res.obtainTypedArray(R.array.ingr_color_arr);
int colorToUse = ta.getResourceId(intGroupNum.intValue() - 1, R.color.recipe_detail_border);
paint.setColor(colorToUse);
The key here is to use getResourceId because setColor(int) is going to expect a resource id for a color. I was getting "Resource not found" errors when I tried getting the value with getIntArray()
or getColor()
.
The most popular answer may work...I didn't try it because I preferred the 'array of colors' design choice better.
In Kotlin that will be much simpler
val colors = resources.obtainTypedArray(R.array.colors).use { ta ->
IntArray(ta.length()) { ta.getColor(it, 0) }
}