How to sort a List<Object> alphabetically using Object name field

Solution 1:

From your code, it looks like your Comparator is already parameterized with Campaign. This will only work with List<Campaign>. Also, the method you're looking for is compareTo.

if (list.size() > 0) {
  Collections.sort(list, new Comparator<Campaign>() {
      @Override
      public int compare(final Campaign object1, final Campaign object2) {
          return object1.getName().compareTo(object2.getName());
      }
  });
}

Or if you are using Java 1.8

list
  .stream()
  .sorted((object1, object2) -> object1.getName().compareTo(object2.getName()));

One final comment -- there's no point in checking the list size. Sort will work on an empty list.

Solution 2:

The most correct way to sort alphabetically strings is to use Collator, because of internationalization. Some languages have different order due to few extra characters etc.

   Collator collator = Collator.getInstance(Locale.US);
   if (!list.isEmpty()) {
    Collections.sort(list, new Comparator<Campaign>() {
        @Override
        public int compare(Campaign c1, Campaign c2) {
            //You should ensure that list doesn't contain null values!
            return collator.compare(c1.getName(), c2.getName());
        }
       });
   }

If you don't care about internationalization use string.compare(otherString).

   if (!list.isEmpty()) {
    Collections.sort(list, new Comparator<Campaign>() {
        @Override
        public int compare(Campaign c1, Campaign c2) {
            //You should ensure that list doesn't contain null values!
            return c1.getName().compare(c2.getName());
        }
       });
   }

Solution 3:

Using Java 8 Comparator.comparing:

list.sort(Comparator.comparing(Campaign::getName));