Warning: mysql_fetch_array(): supplied argument is not a valid MySQL result
I get the error when trying to run this:
<?php
require_once('includes/DbConnector.php');
$connector = new DbConnector();
$result = $connector->query('SELECT title,content FROM staff_vacancies ORDER BY ordering LIMIT 0,100');
// Get an array containing the results.
// Loop for each item in that array
while ($row = $connector->fetchArray($result)){
echo $row['title'].'</h3>';
echo $row['content'];
}
?>
I have a linked file: DbConnector.php:
<?php
////////////////////////////////////////////////////////////////////////////////////////
// Class: DbConnector
// Purpose: Connect to a database, MySQL version
///////////////////////////////////////////////////////////////////////////////////////
require_once 'SystemComponent.php';
class DbConnector extends SystemComponent {
var $theQuery;
var $link;
//*** Function: DbConnector, Purpose: Connect to the database ***
function DbConnector(){
// Load settings from parent class
$settings = SystemComponent::getSettings();
// Get the main settings from the array we just loaded
$host = $settings['dbhost'];
$db = $settings['dbname'];
$user = $settings['dbusername'];
$pass = $settings['dbpassword'];
//the settings
$host = 'localhost';
$db = 'xxx';
$user = 'xxx';
$pass = 'xxx';
// Connect to the database
$this->link = mysql_connect($host, $user, $pass);
mysql_select_db($db);
register_shutdown_function(array(&$this, 'close'));
}
//*** Function: query, Purpose: Execute a database query ***
function query($query) {
$this->theQuery = $query;
return mysql_query($query, $this->link);
}
//*** Function: getQuery, Purpose: Returns the last database query, for debugging ***
function getQuery() {
return $this->theQuery;
}
//*** Function: getNumRows, Purpose: Return row count, MySQL version ***
function getNumRows($result) {
return mysql_num_rows($result);
}
//*** Function: fetchArray, Purpose: Get array of query results ***
function fetchArray($result) {
return mysql_fetch_array($result);
}
//*** Function: close, Purpose: Close the connection ***
function close() {
mysql_close($this->link);
}
}
?>
Does anyone know what the problem is?
Solution 1:
Your query must have a problem which is causing $result to be an invalid resource.
Try checking for mysql_error() after the line on which you run your query.
Edit:
In fact, I would alter your DBConnector class function query() to something like the following, so that an identifiable error is thrown when you have a bad query:
function query($query) {
$this->theQuery = $query;
$queryId = mysql_query($query,$this->link);
if (! $queryId) {
throw new Exception(mysql_error().". Query was:\n\n".$query."\n\nError number: ".mysql_errno();
}
return $queryId;
}
Solution 2:
I find this in a post, to me solved my problem. Slds.
Yeah, Answer is simple, the query used is not a true result as it's a query inside of a getrow so to speak.. Here is the fix: Find all lines that look like this:
mysql_fetch_array(mysql_query("...snip...";-) );
And just add a "@" in front of it so it looks like this:
@mysql_fetch_array(mysql_query("...snip...";-) );
Then do the same thing for the following lines.. Code:
mysql_num_rows(mysql_query("...snip...";-) );
Perform the same steps as above by adding the "@" to it so it looks like this:
@mysql_num_rows(mysql_query("...snip...";-) );
All this does it say "While doing xxx within yyy" Otherwise, it's dead due to missing result value. It's a PHP thing..
Works like a charm, took me 5 mins to rip the whole code apart and slap it all into Modernbill, Shares the same database and works perfectly for me.
Solution 3:
This error means your query failed. mysql_query()
returns false if an error occurred, you are then passing false to mysql_fetch_array()
which is triggering the error message.
Your query could be failing due to a missing/wrong table or field. To see the detailed error, print out the result of mysql_error().
The mysql_*
library is deprecated. It is recommended to upgrade to MySQLi
or PDO.
Solution 4:
// Load settings from parent class
$settings = SystemComponent::getSettings();
// Get the main settings from the array we just loaded
$host = $settings['dbhost'];
$db = $settings['dbname'];
$user = $settings['dbusername'];
$pass = $settings['dbpassword'];
//the settings
$host = 'localhost';
$db = 'xxx';
$user = 'xxx';
$pass = 'xxx';
Did you mean to reassign the connection vars? OR was that a few lines of stub code you forgot to take out? Or just an example to show what $settings contains?