Induction on two integer variables
Here are some induction principles for two variables:
- $P(0,0)$
- $\forall x,y. P(x,y) \Rightarrow P(x+1,y)$
-
$\forall x,y. P(x,y) \Rightarrow P(x,y+1)$
$\forall x,y. P(x,y)$
and
- $P(0,0)$
- $\forall x,y. P(x,0) \Rightarrow P(x+1,0)$
-
$\forall x,y. P(x+1,y) \Rightarrow P(x,y+1)$
$\forall x,y. P(x,y)$
Suppose you are trying to prove a family of statements $P(x, y)$. This is the same as proving the family of statements $F(x)$, where $F(x) = \forall y : P(x, y)$. Each statement $F(x)$ can be proven by induction on $y$ (for fixed $x$), and then you can prove $P(x, y)$ by induction on $x$. You might want to try proving
$${n+1 \choose k+1} = {n \choose k+1} + {n \choose k}$$
this way.
But actually you can be much trickier than this. Sometimes it suffices to induct on $x + y$, for example.