JavaScript, Typescript switch statement: way to run same code for two cases?

Is there a way to assign two different case values to the same block of code without copy and pasting? For example, below 68 and 40 should execute the same code, while 30 is not related.

case 68:
   //Do something
break;

case 40:
   //Do the same thing
break;

case 30:
   //Do something different
break;

Is it incorrect to think something like this should work (even though it obviously doesn't)?

case 68 || 40:
   //Do something
break;

case 30:
   //Do something else
break;

Just put them right after each other without a break

switch (myVar) {
  case 68:
  case 40:
    // Do stuff
  break;

  case 30:
    // Do stuff
  break;
}

Yes, you just put the related case statements next to each other, like this:

case 40:  // Fallthrough
case 68:
   // Do something
   break;

case 30:
   // Do something different
   break;

The Fallthrough comment is there for two reasons:

• It reassures human readers that you're doing this deliberately
• It silences warnings from Lint-like tools that issue warnings about possible accidental fallthrough.

case 68:
case 40:
  // stuff
  break;

Cleaner way to do that 👌

if ([68, 48, 22, 53].indexOf(value) > -1)
    //Do something
else if ([44, 1, 0, 24, 22].indexOf(value) > -1)
    //Do another

You can do that for multiple values with the same result