bash script to check website content by curl command
I want to write a script to check out if the website is working fine by checking out some of it is contents. If the content exists in the result, it prints a message telling the website is working fine, otherwise, it will show an error:
#!/bin/bash
webserv="10.1.1.1"
Keyword="helloworld" # enter the keyword for test content
if (curl -s "$webserv" | grep "$keyword")
# if the keyword is in the conent
echo " the website is working fine"
else
echo "Error"
Any suggestion how to do that?
You're mostly there. Just fix your syntax:
if curl -s "$webserv" | grep "$keyword"
then
# if the keyword is in the conent
echo " the website is working fine"
else
echo "Error"
fi
Note the then
and fi
.
A tiny amend: when setting the variable and using it later, the case needs to match in the two places (ie 'keyword', not 'Keyword'). The full code that works for me:-
#!/bin/bash
webserv="10.1.1.1"
keyword="helloworld" # enter the keyword for test content
if curl -s "$webserv" | grep "$keyword"
then
# if the keyword is in the content
echo " the website is working fine"
else
echo "Error"
fi