Get original indices of a sorted Numpy array
I have an array of distances a = np.array([20.5 ,5.3 ,60.7 ,3.0 ], 'double')
and I need the indices of the sorted array (for example [3, 1, 0, 2]
, for a.sort()
). Is there a function in Numpy to do that?
Solution 1:
Yes, there's the x = numpy.argsort(a)
function or x = numpy.ndarray.argsort(a)
method. It does exactly what you're asking for. You can also call argsort
as a method on an ndarray
object like so: a.argsort()
.
Here's a link to the documentation: http://docs.scipy.org/doc/numpy/reference/generated/numpy.argsort.html#numpy.argsort
Solution 2:
Here's an example, for reference and convenience:
# create an array
a = np.array([5,2,3])
# np.sort - returns the array, sorted
np.sort(a)
>>> array([2, 3, 5])
# argsort - returns the original indexes of the sorted array
np.argsort(a)
>>> array([1, 2, 0])