Python's any() function on a list of lists gives weird outputs
Your syntax is wrong. You are first computing any(a) (which is True) then check if True is in your target list. The reason it sometimes returns True is the fact that int(True) is equal to 1, so it only prints True if your target list contains a 1.
Try this, for example:
print(any(x in [4,5,7,6] for x in a)) # Should print True