output odd numbers without if [closed]

I need to output only odd numbers from this program:

m = int(input())
n = int(input())
for i in range(m, n - 1, -1,):
    print(i)

pls without if

Solution 1:

Using and instead of if:

i&1 and print(i)

(Better use range with step -2, I just dislike such restriction questions and always try to work around the restrictions in unintended ways).

Solution 2:

Without a guarantee that your start value is odd it becomes a little more tricky since you cannot simply step by 2. You can still get away with it(slightly) using conditionals like so:

m = int(input())
n = int(input())
for i in range(m, n):
    output_str = (f"{str(i % 2)}" or "") * i
    output_str += (i % 2) * '\n'
    print(output, end="")

I should put a disclaimer here that I'm strictly answering the question. I do not exactly endorse this method.

Solution 3:

You can use a striding range as long as you make sur to adjust the starting number:

m = int(input())
n = int(input())
for i in range(m+1-m%2,n+1,2): # start at next odd if m is even
    print(i)

If you want them in decreasing order:

m = int(input())
n = int(input())
for i in reversed(range(m+1-m%2,n+1,2)):
    print(i)